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3 years ago

Question two plz :)

Mathematics

2 answers:

notka56 [123]3 years ago

7 0

Bd is perpendicular to ac because it comes from a and cuts the ac into two equal halves and since the triangle is isoceles if any lines comes through a and intersects the base into 2 equal halves that must be perpendicular

alisha [4.7K]3 years ago

6 0

Answer:

BD is perpendicular to AC.

Step-by-step explanation:

Because we know that angles ∠BAD and ∠BCD are the same, we can conclude that triangles ΔABD and ΔBCD are congruent. This means that angles ∠BDA and ∠BDC are right angles, and lines BD and AC are congruent.

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In 1 week there are 7 days how many weeks in 210 days

Lelechka [254]

210/= 30 so the answer is 30

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4 years ago

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Pizazz manufactures a 5.0 oz. energy drink of the same name. Because the cans are so small, consumers are concerned that they ar

omeli [17]

Answer:

The LCL of the R-chart starts from the origin ( i.e. zero value ) while the LCL of an X -chart did not start from the origin

LCL of R-chart = 0 * 0.84533 = 0

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Step-by-step explanation:

Given data:

number of observations = 15

sample size ( m ) = 6

sum of sample mean = 80.20 ounces

sum of sample range ( R ) = 12.68 ounces

Determine the control limits of an x-bar and R-chart

<em>for an R-chart </em>

LCL of R-chart = D3 * R(bar) ---- ( 1 )

where : m = 6 , D3 = 0 , R = 12.68

R(bar) = 0.84533

back to equation 1

LCL of R-chart = 0 * 0.84533 = 0

<em>for an X-chart </em>

LCL of X-bar) = ( mean ) - (m x R-bar)

= 80.20 - ( 6 * 0.84533 )

= 75.128

The LCL of the R-chart starts from the origin ( i.e. zero value ) while the LCL of an X -chart did not start from the origin

3 0

3 years ago

Find the sum of ∠BCD and ∠SBT in terms of x.

AleksAgata [21]

$Let's\ \angle TCB=y^o\\\\\angle SBT\ is\ the\ exterior\ angle\ of\ \Delta TCB,\ therefore\ |\angle SBT|=x^o+y^o.\\\\|\angle\ BCD|\ +\ y^o=180^o-angles\ on\ one\ side\ of\ a\ straight\ line\\\\|\angle BCD|=180^o-y^o\\\\therefor\\\\\angle SBT+\angle BCD=x^o+y^o+180^o-y^o=x^o+180^o\\\\\boxed{Answer:\angle SBT+\angle BCD=x^o+180^o}$

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3 years ago

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astra-53 [7]

Answer:

125

Step-by-step explanation:

120 - 90 = 25 x 5 = 125

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3 years ago

One x-intercept for a parabola is at the point (-0.4,0). Use the quadratic formula to find the other x-intercept for the parabol

navik [9.2K]

Answer:

-1

Step-by-step explanation:

Set y=0.

$5 {x}^{2} + 7x + 2 = 0 \\ x = \frac{ - 7± \sqrt{ {7}^{2} - 4(5)(2)} }{2(5)} \\ x = \frac{ - 7± \sqrt{ 9} }{10} \\ x = \frac{ - 7±3}{10} \\ x = - \frac{2}{5} \: \: \: \: or \: \: \: \: - 1$

The x-intercepts are - 0.4 and - 1.

The other x-intercept is - 1.

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3 years ago