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krok68 [10]
2 years ago
15

Question two plz :)

Mathematics
2 answers:
notka56 [123]2 years ago
7 0
Bd is perpendicular to ac because it comes from a and cuts the ac into two equal halves and since the triangle is isoceles if any lines comes through a and intersects the base into 2 equal halves that must be perpendicular
alisha [4.7K]2 years ago
6 0

Answer:

BD is perpendicular to AC.

Step-by-step explanation:

Because we know that angles ∠BAD and ∠BCD are the same, we can conclude that triangles ΔABD and ΔBCD are congruent. This means that angles ∠BDA and ∠BDC are right angles, and lines BD and AC are congruent.

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The "middle" term of a trinomial form of (3x+1)(x-4) is:
Zarrin [17]

Answer:

Expand the following expression

(3x+1)(x-4) = 3x^2-12x+x-4

middle term = -11x

3 0
2 years ago
If this trapezoid is moved through the
jeka94

Answer:

Step-by-step explanation:

A(-6,2) =>A'(-5, -1)

B(-5,4) =>B'( -4,1)

C(-2,4)=> C'(-1,1)

D( 1,2) => D'(2,-1)

we move all these points to (x+1, y-3)

7 0
2 years ago
Find an equation of the line passing through the pair of points (2,3) and (5,9). Write the equation in the form Ax + By = C.
8090 [49]

Answer:

- 2x +  y  = - 1 , so the B is correct.

Step-by-step explanation:

+ Because of "the line passing through the pair of points (2,3) and (5,9)", that means the line has the equation y = ax + b where a = (9-3)/(5-2)= 6/3= 2

+ So the equation is y = 2x + b.

+ Then we replace x= 2 and y= 3 into y = 2x + b for finding  like:

3 = 2*2 + b or 3 = 4 + b, so we find b = 3 - 4 = - 1.

+ The equation of this line is y = 2x - 1 or in the form:

                                  2x - y - 1 = 0 (or -2x + y = -1)

Have a good day!

7 0
3 years ago
A = 78', b = 12.3, c = 20.2
nasty-shy [4]

Answer:

yay u got your answer:))

but seriously what is your question?:))

5 0
2 years ago
Read 2 more answers
X 3) Find the product of 3 x 4 2/3 * O 18 3/4 O 12 6/3 or 14 o 71/2 (0) 14​
ladessa [460]

D. \: 14 \: ✅

Step-by-step explanation:

3 \times 4 \frac{2}{3}  \\  = 3 \times  \frac{14}{3}  \\ =   14

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

5 0
2 years ago
Read 2 more answers
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