Is a linear model or a quadratic model a better fit? Quadratic model graph quadratic model linear model
1 answer:
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So, since both equate to y, we can solve for x by equating the equations to each other.
4x - 5 = -3
So: 4x = 2
So: x = 1/2, or 0.5
Now, y = -3, so the solution is (0.5, -3)
You can graph the two equations, and the point where they meet will be (0.5, -3).
4x - 5 = -3
So: 4x = 2
So: x = 1/2, or 0.5
Now, y = -3, so the solution is (0.5, -3)
You can graph the two equations, and the point where they meet will be (0.5, -3).
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Answer:
see attached
Step-by-step explanation:
Translation 12 units down puts each point 12 units lower on the graph than the position where it is currently shown. Segment RS is now shown on the line y=9. It will be translated straight down so it appears on the line y = 9-12 = -3.
Similarly, T has a y-coordinate of 2. Translated down 12, it will have a y-coordinate of y = 2-12 = -10.
The x-coordinates of all of the points remain the same.
The translation is shown in the attachment.
