The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
Answer:
r
=
1
Step-by-step explanation:
The GCF here is 2
2(z - 11z + 24)
i assume your question is wrong.. or you printed it inaccurately
because the 1st term should indicate the highest exponent however the 1st and 2nd terms are having the same exponent!!
Answer:
4/5
Step-by-step explanation:
cos B = 3/5
cos Ф = adjacent/hypothesis
hypothesis ² = adjacent² + opposite²
5²= 3²+ o²
25 = 9+o²
25-9=o²
16 = o²
√16 = o = 4
Sin B = opposite/hypothesis = 4/5