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Inessa05 [86]
3 years ago
8

I need help, you’ll receive brainlest!

Mathematics
1 answer:
OleMash [197]3 years ago
5 0

Answer:

D)

Step-by-step explanation:

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Write an equation of a parabola that passes through the point (2,4) with vertex (-1,-1) in vertex form.
quester [9]
An applicable equation of a vertical parabola in vertex form is:

y-k = a(x-h)^2

Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex.  Then,

4-(-1) = a(2-[-1])^2, which becomes 5 = a(9).  Therefore, a = 5/9, and the 
equation of the parabola is

y+1 = (5/9)(x+1)
8 0
3 years ago
Will mark Brainliest!!!!
Zinaida [17]

Answer:

  1. Parallel
  2. Neither parallel nor perpendicular ​
  3. Perpendicular

Step-by-step explanation:

<u>Given line m:</u>

  • y = 4/5x - 3

<u>Relationship of line m with following lines:</u>

1.<u> y = 4/5x + 3</u>

  • Same slope, different y-intercept
  • Parallel

2. <u>y = -4/5x + 3</u>

  • Slope are negative, different y-intercept
  • Neither parallel nor perpendicular ​

3. <u>y = - 5/4x + 3</u>

  • Slopes are negative-reciprocal, different y-intercept
  • Perpendicular
7 0
3 years ago
1. Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial i
Katena32 [7]
Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be  2 - 5i and:

f(x)=\big(x-4\big)\big(x-(-8)\big)\big(x-(2+5i)\big)\big(x-(2-5i)\big)=\\\\=(x-4)(x+8)(x-2-5i)(x-2+5i)=\\\\=(x^2-4x+8x-32)(x^2-2x+5ix-2x+4-10i-5ix+10i-25i^2)\\\\=\big(x^2+4x-32\big)\big(x^2-4x+4-25\cdot(-1)\big)=\\\\=(x^2+4x-32)(x^2-4x+29)=\\\\=x^4-4x^3+29x^2+4x^3-16x^2+116x-32x^2+128x-928=\\\\=\boxed{x^4-19x^2+244x-928}

Answer B.
8 0
3 years ago
Read 2 more answers
What is the value of x?
Aleks04 [339]
The answer of x is
X=84,8
5 0
3 years ago
Find the y-intercept of f(x) = x^3 + 3x^2 - X-3<br> HURRY
Grace [21]

Answer:

y-intercepts: (-3,0) , (-1,0) , (1,0)

Step-by-step explanation:

3 0
3 years ago
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