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3 years ago

– 2y – 10 = x - 10x - y = -14

Mathematics

1 answer:

fredd [130]3 years ago

5 0

Answer:

hey there guys ^^

Step-by-step explanation:

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The zero of F -1(x) in F(x) = x + 3 is

seropon [69]

Answer:

-3

Step-by-step explanation:

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3 years ago

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7r+3r-8=8+2r. Solve?

Mazyrski [523]

Given: 7r+3r-8=8+2r

Simplify: 10r-8=8+2r

Addition: add 8 to each side: 10r=16+2r

Subtraction: Take 2r from each side: 8r=16

Division: Divide each side by 8 for answer: r=2

Answer: r=2

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4 years ago

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Henry wants to estimate the cost of filling his water tank. First, he needs to find the volume of the water tank in order to fil

laila [671]

Answer:

60 ft³

Step-by-step explanation:

2 x 3 x 4 = 24

3 x 3 x (6-2) = 36

24 + 36 = 60

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3 years ago

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What is the length of this rectangular prism?Is it 5 or 3 or 6 or 2

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We can't see the rectangular prism...

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2 years ago

Find the derivative of f(x)= (e^ax)*(cos(bx)) using chain rule

Vikentia [17]

$f(x) = e^{ax}\cos(bx)$

then by the product rule,

$f'(x) = \left(e^{ax}\right)' \cos(bx) + e^{ax}\left(\cos(bx)\right)'$

and by the chain rule,

$f'(x) = e^{ax}(ax)'\cos(bx) - e^{ax}\sin(bx)(bx)'$

which leaves us with

$f'(x) = \boxed{ae^{ax}\cos(bx) - be^{ax}\sin(bx)}$

Alternatively, if you exclusively want to use the chain rule, you can carry out logarithmic differentiation:

$\ln(f(x)) = \ln(e^{ax}\cos(bx)} = \ln(e^{ax})+\ln(\cos(bx)) = ax + \ln(\cos(bx))$

By the chain rule, differentiating both sides with respect to <em>x</em> gives

$\dfrac{f'(x)}{f(x)} = a + \dfrac{(\cos(bx))'}{\cos(bx)} \\\\ \dfrac{f'(x)}{f(x)} = a - \dfrac{\sin(bx)(bx)'}{\cos(bx)} \\\\ \dfrac{f'(x)}{f(x)} = a-b\tan(bx)$

Solve for <em>f'(x)</em> yields

$f'(x) = e^{ax}\cos(bx) \left(a-b\tan(bx)\right) \\\\ f'(x) = e^{ax}\left(a\cos(bx)-b\sin(bx))$

just as before.

4 0

3 years ago