Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
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There are four terms and it is sum !
so the answer is C !!
Answer:
no 0.05 is smaller then 0.083
Step-by-step explanation:
Answer:
Option A and Option C
Step-by-step explanation:
Option A: 
This is completely factored as 8 is the Highest Common Monomial factor
Option B: 
This is not completely factored as 2 is still a common factor of 6y2 and -2.
Option C: 
This is completely factored as 4y2 is the Highest Common Monomial factor
Option D: 
This is not completely factored as 2y is still a common factor of 4y6 and 2y.
So the options that are completely factored are Option A and Option C
Multiply the length by width by the height/3
7 x 6 x 8/3 = 112 in^2
The answer is 112 in^2
