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Arte-miy333 [17]
1 year ago
5

Hello the question is in the picture ( only C)

Mathematics
1 answer:
pav-90 [236]1 year ago
6 0

SOLUTION:

A normal distribution would model this situation because the distribution is approximately symmetrical, thus the mean, median and mode are approximately the same and the population size is large ( greater than 30).

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A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep
Lady bird [3.3K]

The teacher chose option 2, the Starfish and it was valued at $35,200 after two months.

Step-by-step explanation:

Step 1; The Zoomba is priced at $60,000 and has an expected depreciation of 2% per month. So the annual depreciation is 12 months * 2% per month = 24% per year. The teacher plans to keep either car for two years do total depreciation is 2 years * 24% depreciation per year = 48 % in two years.

Value of car after two years = Buying price - Depreciation amount

= $60,000 - 48% of $60,000 = $60,000 - 0.48*$60,000 = $31,200

The car will be valued at $31,200 after two years. To determine how much value it has retained we divide the value in two years to the current value i.e $31,200 divided by $60,000 which equals 0.52 (52% of initial price)

Step 2; The Starfish is priced at $40,00 and will depreciate $200 every month. For a year it will depreciate 12 months * $200 per month = $2,400 a year. So for a total of two years a depreciaition of $4,800.

Value of car after two years = Buying price - Depreciation amount

= $40,000 - $4,800 = $35,200

The car will be valued at $35,200 after two years. To see the retained value we divide the depreciated value by the current value i.e. $35,200 divided by $40,000 which equals 0.88 (88% of the initial price)

Step 3; Of the two options, the Starfish retains more of its value over two years. So the teacher chose the Starfish over the Zoomba.

7 0
4 years ago
Find the root(s) of the equation x2 = 1212
fredd [130]

Answer:

47

Step-by-step explanation:

it's the answer so in conclusion it's the answer

4 0
3 years ago
Can someone do this for me pls?
Yuri [45]
1. 13/4
2. 35/4
3. 11/2
4. 52/77
5. 32/3
6. 232/35
7. 32
8. 5/2
9.217/48
4 0
3 years ago
3. According to the U.S. census website (www.census.gov), based on the U.S. population in 2010, the probability that a randomly
Oksi-84 [34.3K]

Answer:

a. 0.017

b. 0.013

c. 0.021

Step-by-step explanation:

Let p be the probability that a randomly selected man is 65 or older

And q be the probability that a randomly selected woman is 65 or older

Then p=0.114 and q=0.146

Using the multiplication rule for independent events:

a. If a man is selected at random and a woman is selected at random, the probability that both people selected are 65 or older is p × q = 0.114 × 0.146 ≈ 0.017

b. If two men are selected at random, the probability that both of them are 65 or older is p × p = 0.114 × 0.114 ≈ 0.013

c. If two women are selected at random, the probability that neither of them is 65 or older is q × q = 0.146 × 0.146 ≈ 0.021

7 0
4 years ago
To the nearest tenth, what is the value of P(C|Y)? 0.4 0.5 0.7 0.8
erica [24]

Answer:

P(C|Y) = 0.5.

Step-by-step explanation:

We are given the following table below;

               X             Y               Z             Total

A             32           10             28              70

B              6             5              25              36

C             18            15              7                40

Total       56           30            60              146

Now, we have to find the probability of P(C/Y).

As we know that the conditional probability formula of P(A/B) is given by;

                    P(A/B) =  \frac{P(A \bigcap B)}{P(B)}

So, according to our question;

P(C/Y) =  \frac{P(C \bigcap Y)}{P(Y)}

Here, P(Y) = \frac{30}{146} and P(C \bigcap Y) =  \frac{15}{146}  {by seeing third row and second column}

               

Hence, P(C/Y) =  \frac{\frac{15}{146} }{\frac{30}{146} }

                       =  \frac{15}{30}  = <u>0.5.</u>

4 0
3 years ago
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