Answer:
Step-by-step explanation:
IQR is the difference between Q3 and Q1
<u>According to the top box plot:</u>
<u>The IQR is:</u>
Distribute: 3x+6+4=5x+7
Simplify: 3x+10=5x+7
Subtract 3x from both sides: 10=2x + 7
Subtract 7 from both sides: 3=2x
Divide by 2: x=3/2
x=3/2
Answer:
C. $97
Step-by-step explanation:
The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.
average wage for 15 days = (sum of wages for the 15 days)/15
The amount of wages during a number of days is the product of the average wage of those days and the number of days.
First 7 days:
average wage: $87
number of days: 7
total wages in first 7 days = 7 * $87/day = $609
Last 7 days:
average wage: $92
number of days: 7
total wages in last 7 days = 7 * $92/day = $644
8th day:
wages of the 8th day is unknown, so we let x = wages of the 8th day
total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)
total wages of 15 days = 609 + x + 644 = x + 1253
average wage for 15 days = (sum of wages for the 15 days)/15
average wage for 15 days = (x + 1253)/15
We are told the average for the 15 days is $90/day.
(x + 1253)/15 = 90
Multiply both sides by 15.
x + 1253 = 1350
Subtract 1253 from both sides.
x = 97
Answer: $97
Answer:
Solution : (15, - 11)
Step-by-step explanation:
We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )
Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )
Row Echelon Form :
Step # 1 : Swap the first and second matrix rows,
Step # 2 : Cancel leading coefficient in row 2 through 
,
Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.
As you can see our solution is x = 15, y = - 11 or (15, - 11).
Answer:
Step-by-step explanation:
One equivalent can be obtain by distributing multiplication with 3 over subtraction 5-2i
3(5-2i) =
3·5 -3·2·i =
15 -6i or -6i +15
