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Semmy [17]
3 years ago
11

Help with 10 c). Plssss

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer: It’s B or E I would go with id say E

Step-by-step explanation:

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In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per
Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, P_0=450,000

Growth rate is, r=5\%=0.05

Final population is, P=700,000

A population growth is an exponential growth and is modeled by the following function:

P=P_0(1+r)^x

Taking log on both sides, we get:

\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}

Plug in all the given values and solve for 'x'.

x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10

So, for x > 9.13, the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0
3 years ago
PLEASE HURRY I NEED YOUR HELP! show work
8090 [49]

Answer:

1) 10

- 3 3/8

________

=6 5/8

2)  1/5= 2/10

2/10

+ 20 3/10

+ 5 6/10

_________

25 11/10

= 26 1/10

3) 11/12

+ 10

- 10/12

________

= 10 1/12

5 0
3 years ago
Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack
Rainbow [258]

Answer:

2

Step-by-step explanation:

Given the question :

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?

Number of granolas = 6

Number of dried fruits = 10

Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)

____6____10

2___3____5

Here, the highest common factor of 6 and 10 is 2

Hence, the greatest number of snack bags she can make is 2.

5 0
3 years ago
Which of the following illustrates the truth value of the following mathematical statements? 6 + 3 = 9, and 5 • 5 = 20
aleksley [76]
You answer should be
C. T F → F
6 0
4 years ago
A binomial probability distribution has p = .20 and n = 100.
AleksAgata [21]

Answer:

Mean = 0.2(100) = 20

Variance = 0.2×0.8×100 = 16

Standard deviation = 4

Yes, np > 5 & nq > 5

3 0
3 years ago
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