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Tamiku [17]
3 years ago
15

60 twenty-fives minus 1 twenty-five

Mathematics
2 answers:
makkiz [27]3 years ago
5 0
60 twenty fives minus one twenty five is 59x25 is 1475.
9966 [12]3 years ago
5 0

Answer:

60 twenty fives minus 1 twenty five is:

59 twenty fives that is equal to 1425

Step-by-step explanation:

We need to know the difference between 60 twenty fives and 1 twenty five, so:

60(25)-1(25)

We have common factor, 25

25(60-1)\\59(25)=1475

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anastassius [24]
1.666666666666667 to be exact, but rounded it is 1.66
3 0
3 years ago
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Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
1. Juan bought a pair of shoes costing P923.00 and a tie costing P275.00. He gave the seller P2, 000.00. How much change did he
EleoNora [17]
2000.00-923.00-275.00=802.00
4 0
3 years ago
Please help!<br> Please?
yuradex [85]
1. x - y
2. xy
3. y / x
4. x+y
5. y= x-6
6. 6x =y
7. y-x
8. x/y
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10. xy= 6
3 0
3 years ago
Last year Golden State Warriors won 80% of the first 15 matches. Then they won the rest of the three matches. What percent of al
MrMuchimi

Answer:

83.33%

Step-by-step explanation:

We first need to evaluate 80% of the first 15 matches in order to determine the number of watches out of 15 which they won.

80 % of 15 = 80/100 * 15 = 12

12 matches out of the first 15 were won.

Since the team won the rest of the 3 remaining matches, the total number of matches won becomes;

12 + 3 = 15

The team thus won 15 matches out of a total of 15 + 3 =18 matches .

The percent of all matches won is ;

15/18 * 100 = 83.33%

3 0
3 years ago
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