All categories

3 years ago

Compare the 2 ratios by entering >,<,or = in the box

Mathematics

1 answer:

Kamila [148]3 years ago

3 0

Answer:

I don't see any ratios to compare.

Step-by-step explanation:

You might be interested in

Factor: x2 + 9x - 36

blagie [28]

Answer:

11x-36

for your answers

7 0

3 years ago

Read 2 more answers

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

3 years ago

Read 2 more answers

Plsssssss helpppp meeeeeeee I need the procedure and the correct answer plssssssss helppppp

Mumz [18]

Circumference of a circle is 2(pi)(r)
2(3.14)(7)= 43.96
So the answer is B

8 0

3 years ago

Find the value of the expression 9.18 · z for z = 2.

loris [4]

Answer: 18.36

Step-by-step explanation:

Replace "z" with "2":

$9.18 \cdot 2 = \boxed{18.36}$ .

8 0

3 years ago

Please help!!!! Solve the formula A = /w for l.

alexdok [17]

A = wl

Simply divide both sides by w. This is done to isolate the variable we are solving for.

A/w = (wl)/w

A/w = l

Answer: Choice C

6 0

3 years ago

Compare the 2 ratios by entering >,<,or = in the box​

Compare the 2 ratios by entering >,<,or = in the box