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3 years ago

Please help me i will give you 100 points :D

Mathematics

2 answers:

AleksandrR [38]3 years ago

7 0

Answer:

9 hours

Step-by-step explanation:

Firstly the would add 1 1/2 and 2 1/2.

Then you would add 2

Lastly you would add 3

Therefore, your answer would be 9 hours.

Eduardwww [97]3 years ago

3 0

Answer:

9 hours in total

Step-by-step explanation:

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A spinner numbered 1 through 12 is spun. Find the probability that

anastassius [24]

Answer:

$\dfrac{1}{6}$

Step-by-step explanation:

Let A be the event of getting an odd number.

P(A) be the probability of getting an odd number.

Total odd numbers here are 6 i.e. $\{1,3,5,7,9,11\}$

Here, total numbers in the game are 12 i.e $\{1,2,3,....,12\}$ .

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}$

Let B be the event of getting 11.

P(B) be the probability of getting 11.

Total number of possible cases is 1.

$P(B) = \dfrac{1}{12}$

$P(A \cap B)$ is the probability that we get 11 and an odd number.

Possible number of cases = 1

$P(A\cap B) = \dfrac{1}{12}$

P(B/A) is the probability that we get an 11 given that it is an odd number.

$P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}$

Hence, P(B/A) = $\dfrac{1}{6}$

4 0

4 years ago

Read 2 more answers

23,674=38 --------------- b

Maru [420]

Is there a picture or is it just that

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3 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$