Question

Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)

Answer 1

Answer:

Answer:

Step-by-step explanation:

Slope of a line 2x+3y=6 is -2/3

So line passing through (0,4) has same slope because both are parallel

From slope intercept form we have

Y-y1 =m(x-1)

Y-4= -2/3(x-0)

3Y-12 = -2x

3Y+2x = 12

Which is required equation of a line.

Step-by-step explanation:

Answer 2

Answer:

y = -2/3x + 20/3

Step-by-step explanation:

2x + 3y = 6

3y = -2x + 6

y = -2/3x + 2

y = -2/3x + b

4 = -2/3(4) + b

4 = -8/3 + b

20/3 = b