Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)
2 answers:
Answer:
Answer:
Step-by-step explanation:
Slope of a line 2x+3y=6 is -2/3
So line passing through (0,4) has same slope because both are parallel
From slope intercept form we have
Y-y1 =m(x-1)
Y-4= -2/3(x-0)
3Y-12 = -2x
3Y+2x = 12
Which is required equation of a line.
Step-by-step explanation:
Answer:
y = -2/3x + 20/3
Step-by-step explanation:
2x + 3y = 6
3y = -2x + 6
y = -2/3x + 2
y = -2/3x + b
4 = -2/3(4) + b
4 = -8/3 + b
20/3 = b
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Answer:
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Step-by-step explanation:
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