Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)

Mathematics

2 answers:

wariber [46]3 years ago

7 0

Answer:

Answer:

Step-by-step explanation:

Slope of a line 2x+3y=6 is -2/3

So line passing through (0,4) has same slope because both are parallel

From slope intercept form we have

Y-y1 =m(x-1)

Y-4= -2/3(x-0)

3Y-12 = -2x

3Y+2x = 12

Which is required equation of a line.

Step-by-step explanation:

Colt1911 [192]3 years ago

6 0

Answer:

y = -2/3x + 20/3

Step-by-step explanation:

2x + 3y = 6

3y = -2x + 6

y = -2/3x + 2

y = -2/3x + b

4 = -2/3(4) + b

4 = -8/3 + b

20/3 = b

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cluponka [151]

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Answer:

-13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

$\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}$