Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)
2 answers:
Answer:
Answer:
Step-by-step explanation:
Slope of a line 2x+3y=6 is -2/3
So line passing through (0,4) has same slope because both are parallel
From slope intercept form we have
Y-y1 =m(x-1)
Y-4= -2/3(x-0)
3Y-12 = -2x
3Y+2x = 12
Which is required equation of a line.
Step-by-step explanation:
Answer:
y = -2/3x + 20/3
Step-by-step explanation:
2x + 3y = 6
3y = -2x + 6
y = -2/3x + 2
y = -2/3x + b
4 = -2/3(4) + b
4 = -8/3 + b
20/3 = b
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if the diameter of it is 12, its radius is half that or 6.
Step-by-step explanation:
We have 3(x + 3) = 10 + 2(x - y).
=> 3x + 9 = 10 + 2x - y
=> x = 1 - y
=> y = 1 - x.
(Rewritting it as a mathematical statement is the 1st line)
Answer:
Slope = 0.75
Step-by-step explanation:
Slope is coefficient of x
Z - z + 3 = z + 5
0 + 3 = z + 5
3 = z + 5
3 + z = 5
This can be simplified to 3 + z = 5.
This has one solution, 2.
