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2 years ago

Write a inequality phrase: you have to be at least 21 years of age

Mathematics

2 answers:

lapo4ka [179]2 years ago

7 0

Answer:

a≥ 21

Step-by-step explanation:

Let a = age

At least means greater than or equal to

a≥ 21

SVETLANKA909090 [29]2 years ago

4 0

Answer:

$a\geq 21$

Step-by-step explanation:

"At least" is inclusive, so you can be 21 years old.

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Titus drew a circle with his compass. The circle has five central angles. Four of the angles measure 55°, 37°, 96°, and 88°. Wha

Fiesta28 [93]

Answer:

84°

Step-by-step explanation:

The circle has five central angles that together equal to 360°.

55° + 37° + 96° + 88° = 276°

Hence, to find the fifth central angle, we have to subtract 276° from 360°.

360° - 276° = 84°

The degree measure of the last central angle is 84°.

Hope this helps! :)

3 0

1 year ago

Read 2 more answers

Whats the answer to 0.8 divided by 697.04 show work please.

Varvara68 [4.7K]

Answer:

.00114771

hope this helps, good luck :)

4 0

2 years ago

How do you use math every day?

puteri [66]

Answer:

Figuring out distance, time and cost for travel

shopping for the best price

Step-by-step explanation:

7 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago

Como se calcula la medida de la sircunferencia si conocen la medida del diámetro

anygoal [31]

Para encontrar la medida de la circunferencia se aplica la ecuación P = π*D.

Explicación.

El perímetro es la medida total de todos los lados que pueda tener una figura geométrica, además se tiene que tener en cuenta que es una magnitud fundamental de los polígonos.

Para una circunferencia el perímetro se encuentra multiplicando el diámetro y el número π (pi), como se muestra a continuación:

P = π*D

Dónde:

P es el perímetro.

D es el diámetro

4 0

3 years ago