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gizmo_the_mogwai [7]

3 years ago

10

Which expressions are equivalent to 4-3/4-1

2 answers:

sdas [7]3 years ago

8 0

Answer:

1/3

Step-by-step explanation:

Simplify 4-3 = 1 and 4-1 =3 so itd be 1/3

Mnenie [13.5K]3 years ago

5 0

1/3, 0.3, 3^-1 please mark me brainliest

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3 years ago

Ted says that 3 tenths multiplied by 100 equal 300 thousandth is he correct use a place value chart to explain

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8 0

3 years ago

4. 9d - 5 = 4<br><br> What does d =<br> 5. 6-3w=-27 what does w =<br> 6. -4= q/8-19 what does q =

trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

<em>4)</em> $9d - 5 = 4$

Adding 5 on both the sides ,

$= > 9d - 5 + 5 = 4 + 5$

$= > 9d = 9$

Dividing both the sides by 9 ,

$= > \frac{9d}{9} = \frac{9}{9}$

$= > d = 1$

<em>5)</em> $6 - 3w = - 27$

Substracting 6 from both the sides ,

$6 - 3w - 6 = - 27 - 6$

$= > - 3w = - 33$

Dividing both the sides by -3 ,

$= > \frac{ - 3w}{ - 3} = \frac{ - 33}{ - 3}$

$= > w = 11$

<em>6)</em> $- 4 = \frac{q}{8} - 19$

Adding 19 on both the sides ,

$\frac{q}{8} - 19 + 19 = - 4 + 19$

$= > \frac{q}{8} = 15$

Multiplying both the sides by 8 ,

$= > \frac{q}{8} \times 8 = 15 \times 8$

$= > q = 120$

6 0

3 years ago

Consider the function f(x) = ex and the function g(x), which is shown below. How will the graph of g(x) differ from the graph of

SIZIF [17.4K]

Answer: Option C

Step-by-step explanation:

If the graph of the function $g(x)=f(x) +b$ represents the transformations made to the graph of $y= f(x)$ then, by definition:

If $b> 0$ the graph moves vertically upwards.

If $b$ the graph moves vertically down

In this problem we have the function $g(x)=e^x+5$ and our parent function is $f(x) = e^x$

therefore it is true that $b =5 > 0$

Therefore the graph of $f(x)=e^x$ is moves vertically upwards by a factor of 5 units.

The answer is the Option C: "The graph of g(x) is the graph of f(x) shifted up 5 units"

6 0

3 years ago

Someone please help.

Alexxandr [17]

Hi there!

$f(x)+f(x+1)=4f(x)$

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that $f(x)=3^x$ :

⇒ $f(x)=3^x$ :

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function $f(x)=3^x$ :

⇒ $f(x+1)=3^x^+^1$

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function $f(x)=3^x$ by 4:

$4f(x)=4*3^x$ :

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation $f(x)+f(x+1)=4f(x)$ :

$f(x)+f(x+1)=4f(x)$

$3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x$

Factor the left side

$3^x*(1+3)=4*3^x$

Divide both sides by 3^x

$1+3=4\\4=4$

Because this equation is true, $f(x)+f(x+1)=4f(x)$ is therefore true.

I hope this helps!

3 0

3 years ago