Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
The Vertex of f(x)=|5x|+2 is (0,2)
and vertex of f(x)=|5x|-2 is (0,-2)
Answer:
2
Step-by-step explanation:
there is 2: 3<u> 1 </u>
4
<span>0.48333333333 or if u round it off it would be 0.48</span>
Answer:
57.142858%
Step-by-step explanation:
I didn't know if you wanted the entire answer, so I just gave it anyway.
