I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:
3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4
From absolute value definition you've got two ways:
x-3=4 or x-3=-4
x=7 or x=-1
And answer d) passes
Answer:
4th and 5th option
Step-by-step explanation:
you can easily add eqn 1 and 2 to get rid of the y term for 4th option and get rid of x term by addition as well for the 5th option
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Answer: I cant see the full question but I would say figure D
Step-by-step explanation:
30/20 in half is 15/10
also between 12/8 and 18/12 is 15/10
