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4 years ago

How many times smaller is 3 × 10-5 than 6 × 10-4? NEED HELP PLZ

Mathematics

1 answer:

marta [7]4 years ago

8 0

Answer:

B..........................

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You expect to have the given amount in an account with the given terms. Find how much you can withdraw periodically in order to

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3 years ago

You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?

Serjik [45]

Answer:

120 meters

Step-by-step explanation:

40x3 because the ball went up with a velocity of 40 meters a second and it went for 3 seconds so 40+40+40=120 or 40x3=120 (if this is wrong I'm sorry)

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2 years ago

Read 2 more answers

HELLP PLZ

Alenkasestr [34]

The answer is A.
Step by step explanation:
28/8=3.5

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3 years ago

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Which of the following could be the areas of the three squares shown?

matrenka [14]

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Step-by-step explanation:

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3 years ago

Demand The demand function for a product is given by

stira [4]

Answer:

$x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}$

a) $x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027$

b) $x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294$

Step-by-step explanation:

For this case we have the following function:

$P= 8000 (1- \frac{5}{5 +e^{-0.002 x}})$

We can solve for x like this. First we can reorder the expression like this:

$\frac{P}{8000} = 1- \frac{5}{5+e^{-0.002x}}$

$\frac{5}{5+e^{-0.002x}} = 1 -\frac{P}{8000} = \frac{8000-P}{8000}$

$\frac{40000}{8000-P} = 5 + e^{-0.002x}$

Now we can apply natura log on both sids and we got:

$ln[\frac{40000}{8000-P} -5] = ln e^{-0.002x}$

$ln [\frac{5P}{8000-P}] = -0.002x$

And if we solve for x we got:

$x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}$

Part a

For this case we can replace P = 200 and see what we got for x like this:

$x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027$

Part b

For this case we can replace P = 800 and see what we got for x like this:

$x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294$

4 0

3 years ago