Answer: 10 and 11
Step-by-step explanation: The best way to think about it is to think of the squares of numbers that equal close to 104. 10 squared is 100, and 11 squared is 121. Since 104 is between these two, we can assume that the square root of 104 must be in between their square roots, 10 and 11.
Answer:
jssjsjjsjsjsjsjsjsjsjs
Step-by-step explanation:
jsjsjsjsjssjsjsjsjsjsj
In finding this value you average lower and upper bound
(0.6+0.82)/2 = 0.71
=0.71 estimated
margin of error = distance from estimate point lower/ upper bound
This interval will be twice margin error
(0.82-0.6)/2 = 0.11
How far is 0.82 from 0.71 ??
=0.11=11%
Answer:
x=2 and y=3.
Step-by-step explanation:
Let the one number be x and the other number be y.
ATQ, 2x=1+y and x+y=5. x=2 and y=3.
