1. The percent probability that the first child of the couple will have Huntington's disease is 50%
2. The percent probability that four of the seven children will have Huntington's disease is 6.25%
<h3>Genetical probabilities</h3>
The disease is autosomal dominant. Only one dominant allele is needed for the disease to be manifested.
The husband is Hh and the wife is hh.
Hh x hh
Hh Hh hh hh
Hh (affected) = 1/2
hh (unaffected) = 1/2
1. Probability that the first child of this couple will have Huntington's disease is the same as the probability of having the disease. Thus, it is 1/2 (50%)
2. Probability that four of the seven children will have Huntington's disease is the same as the probability of having the disease in 4 places.
1/2 x 1/2 x 1/2 x 1/2 = 1/16 or 6.25%
More on genetic probabilities can be found here: brainly.com/question/13764507
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The change in partial pressure from the alveoli (high concentration) to
the capillaries (low concentration) drives the oxygen into the tissue
and the carbon dioxide into the blood (high concentration) from the
tissues (low concentration), which is then returned to the lungs and
exhaled.
Once in the blood of the capillaries, the O2 binds to the
hemoglobin in red blood cells which carry it to the tissues where it
dissociates to enter the cells of the tissues.
The lungs never fully
deflate, so air that is inhaled mixes with the residual air left from
the previous respiration, resulting in a lower partial pressure of
oxygen within the alveoli.
Bcoz.. In meiosis ti change ploidy of cell from diploid(n) to haploid(2n) .. 2 division occur.. This helps in formation of haploid gametes.. When two gametes fuse.. They form diploid (2n) zygote.
On the other hand..
There is only one division in mitosis...bcoz no change in ploidy.. Use in growth. Bcoz it retains nucleo-cytoplasmic ratio.
Answer:
a animal cell it tiny little pieces in the animal bodies
Answer:
Endothermic since it takes place in the egg :)
