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Mathematics

2 answers:

Agata [3.3K]3 years ago

7 0

The answer is I think $50

Katena32 [7]3 years ago

6 0

Can you try typing the question I can’t see it from the photo

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I promise i will mark as brainiest

Katyanochek1 [597]

Answer:

Step-by-step explanation:

$\frac{2003}{n} = z + \frac{23}{n}$

where z is an integer

$2003 = nz + 23$

$nz = 1980$

$nz = {2}^{2} \times {3}^{2} \times 5 \times 11$

possible values of n

n= {1980, 990, 660, 495, 396, 330, 198, 180, 165, 132, 99, 90, 60, 45, 36, 30, 20, 18, 15, 5, 3}

cardinality of n=21

8 0

3 years ago

Find the 6th term of the geometric progressive (go) -108,-36,-12...

zhannawk [14.2K]

Answer:

-108, -36, -12, -3, -1, -.333333

Step-by-step explanation:

6 0

3 years ago

95% of students at school weigh between 62 kg and 90 kg. Assuming this data is normally distributed, what are the mean and stand

stiks02 [169]

We can calculate (62 + 90) / 2 = 76. it's known that 95% lies between the mean and twice the standard deviation. if the mean is "μ" and the standard deviation is "σ": μ-2σ and μ+2σ. if μ=76, then 76+2σ = 90, so 2σ = 14, so σ = 7.

the mean is 76 and the standard deviation 7.

5 0

3 years ago

Read 2 more answers

Students in a statistics class conduct a survey to estimate the mean number of units students at their college are enrolled in.

WINSTONCH [101]

Answer:

True

Step-by-step explanation:

The margin of error of a confidence interval is given by:

$M = z*\frac{\sigma}{\sqrt{n}}$

In which z is the critical value related to the confidence level, $\sigma$ is the standard deviation of the population and n is the size of the sample.