Question

In ∆ABC, m∠BAC=4x+10,m∠ABC=12x-6,and m∠BCA=3x+5

Answer 1

Answer:

Try this option, note: only calculation is performed, the last two question are missed.

Step-by-step explanation:

to calculate 'x':

the rule: m∠BAC+m∠ABC+m∠BCA=180°; if to substitute m∠BAC=4x+10,m∠ABC=12x-6,and m∠BCA=3x+5, then 4x+10+12x-6+3x+5=180°; ⇔ x=9.

to calculate m∠BAC; m∠ABC; m∠BCA:

m∠BAC=4x+10; ⇒ m∠BAC=36+10=46°;

m∠ABC=12x-6; ⇒ m∠ABC=108-6=102°;

and m∠BCA=3x+5; ⇒ m∠BCA=27+5=32°.

to calculate the angle 1 and 2:

the fule is: m∠1+m∠BAC=180° and m∠2+m∠ABC=180°.

Then m∠1=180-m∠BAC=180-46=134°;

m∠2=180-m∠ABC=180-102=78°.