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Margarita [4]
2 years ago
6

You just got a free ticket for a boat ride, and you can bring along 2 friends! Unfortunately, you have 6 friends who want to com

e along.
How many different groups of friends could you take with you?
Mathematics
2 answers:
ladessa [460]2 years ago
5 0

Answer:

10

Step-by-step explanation:

Maslowich2 years ago
5 0
You can bring 3 groups of 2 people along with you on the boat ride
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What percentage is 285 feet of an acre
Aleksandr-060686 [28]
Since there are 43560 feet in an acre, 285 feet is 0.654% of an acre.
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3 years ago
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PLEASE HELP:
Kryger [21]
Alright so lets start with an arbitrary amount of students. Just to help us visualize the problem.

Say, 100 students for the first year when it was founded?

So far,
1996 - 100 students

From 96' to 97', it doubles. So:
1996 - 100 students
1997 - 200 students

From 97' to 98', it doubles AGAIN.
1996 - 100 students
1997 - 200 students
1998 - 400 students

So, what the percentage increase from 100, to 400?

Well, 100 x 4 gives us 400, so it's a 400 percent increase.
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3 years ago
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What is the vertical distance from the origin to the point (2,9)
Ksenya-84 [330]

Answer: The answer should be 9.2195

Step-by-step explanation:They tell us the point is 2.9 and they are asking the distance from the origin which is zero. So we can use pythagorean theorem. A²+B²=C² Look at it as a triangle. They have given us A and B, so you can find C² using those information. If you plot the point in the line you know that A=2 and B=9. Using the formula will be 2²+9²=C² ⇒ 4+81=C² ⇒ 85=C². To get rid of the power of 2 in c we have to square both side to cancel it out. C would equal 9.2195

3 0
3 years ago
A community theater sold 400 tickets
Romashka-Z-Leto [24]
And what happened?
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5 0
2 years ago
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A researcher wants to test if the mean annual salary of all lawyers in a city is different from $110,000. A random sample of 50
KiRa [710]

Solution :

This is the two tailed test.

The null hypothesis and the alternate hypothesis is as :

Null hypothesis is $H_0:\mu=110000$

Alternate hypothesis is $H_0:\mu \neq110000$

$\overline x = 112000, \ \mu = 110000, \sigma = 16100, n =  50, \alpha = 0.02$

Therefore, the critical value of z is :

$z_{\alpha} = -2.33 \text{ and}\  2.33$

Now the test statics is :

$z=\frac{\frac{(\overline x - \mu)}{\sigma}}{\sqrt n}$

$z=\frac{\frac{(112000-110000)}{16100}}{\sqrt {50}}$

$z=0.87$

The test statics is 0.878

We see that it is a right tailed test.

$P(z > 0.878)=1-P(z

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Thus , P-value > α

So we fail to reject the null hypothesis.

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2 years ago
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