86/5
= 85/5 + 1/5
= (17x5)/5 + 1/5
= 17 + 1/5
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
a₁ = 4
n = 10
d = 3
a = a₁ + (n - 1)d
a₁₀ = 4 + (10 - 1)3
a₁₀ = 4 + (9)3
a₁₀ = 4 + 27
a₁₀ = 31
The 10th term would be 31 and the d variable will be replaced with the number 3.
Answer:
I'm not going to give you the answer because you need to learn this on your own because it isn't hard.
Step-by-step explanation:
There are 4 main things you investigate in a number line: the median, the mode, the range, and mean. The median is the middle of your data set. You find the number of all of your data and find out the middle of that number. You find what line it is in on your data set. The range is the variety of numbers in your data set (for yours its 10). The mean is the average of your data set. The mode is the number that pops up the most (in your case, 2).
Callum must buy one packet of dog food every 10 days
