Answer:
The time required to text 126 words is = 9 minutes
Step-by-step explanation:
Given data
William can text 84 words in 6 minutes
Time required for text one word = 
minute
Therefore the time required to text 126 words is given by
T = Time required for text one word × Total no. of words
T = × 126
T = 9 minutes
Therefore the time required to text 126 words is = 9 minutes
The question tells us that Mallory's 2 years old than three times her brother Jake's age, but let's just start by saying she's 2 years older than <em>some age. </em>What would that look like? Well, we'd be taking some number and adding two to it, so something like this:
Mallory's age = (some age) + 2
What is that age though? The problem tells us it's three times Jake's age, j. We can write that as 3 × j, or 3j, to save space. Filling in our blank, we can write the expression for Mallory's age as 3j + 2
Answer:
9.5 units
Step-by-step explanation:
Let's solve your equation step-by-step.<span>0=<span><span><span>13</span><span>x2</span></span>−3</span></span>Step 1: Subtract 1/3x^2 from both sides.<span><span>0−<span><span>13</span><span>x2 </span></span></span>= <span><span><span><span>13</span><span>x2</span></span>−3</span>−<span><span>13</span><span>x2</span></span></span></span><span><span><span><span>−1</span>3</span><span>x2 </span></span>= <span>−3</span></span>Step 2: Divide both sides by (-1)/3.<span><span><span><span><span>−1</span>3</span><span>x2 </span></span><span><span>− 1</span>3</span></span>=<span><span>− 3 </span><span><span>−1</span>3</span></span></span><span><span>x2 </span>= 9</span>Step 3: Take square root.<span>x=<span>±<span>√9</span></span></span><span><span>x=<span><span>3<span> or </span></span>x</span></span>=<span>−3</span></span>Answer:<span><span>x=<span><span>3<span> or </span></span>x</span></span>=<span>−<span>3</span></span></span>
Answer:
The answer is "Choice D".
Step-by-step explanation:
Please find the complete question in the attached file.
It might indeed multiply that each coordinated throughout this question and construct a delay. In this question, The c instant of differentiation to go and get a smaller image is less than 1, and construct a smaller polygon, that polygon would be extended on even metering systems. Its polygon is distributed out by using the source as the dilation core.
