The answer is 1/2 (; do u need any more help?
Answer:
y+8=16(x-8)
Step-by-step explanation:
y-y1=m(x-x1) is the formula
Just substitute from the first pair then you should get the answer.
First, square both sides. This will cancel out the radical.
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
f(x)= -2x+1 {-2,0,2,4,6}
If x=-2, then -2(-2)+1 = 5
If x=0, then -2(0)+1 = 1
If x=2, then -2(2)+1 = -3
If x=4, then -2(4)+1 = -7
If x=6, then -2(6)+1 = -11
Answer:
B {5,1,-3,-7,-11}
Thee function is given as:
<span>v(t)=t^2−2tv(t)=t^2−2t
</span>(a) What is the initial velocity?
Base from the function, the initial velocity would be zero.
(b) When does the object have a velocity of zero?
It would be during time zero. Also, at a time equal to two.
