Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0

3 0

3 years ago

NO WRONG ANSWERS Two customers took out car loans from a bank. Marcus took out a 5-year loan for $10,000 and paid 4.7% annual si

Gennadij [26K]

Answer:

2164 dollars

Step-by-step explanation:

8 0

2 years ago

Are the length of a side of a square and the perimeter of the square related proportionally? Why or why not?

mariarad [96]

Yes it is because 4 times the length of a side of a square equals to the perimeter of the square

Hope this helps!

Plz give me brainliest answer!!:):)

3 0

2 years ago

20 Point!

ludmilkaskok [199]

determinant: $\sqrt{b^2-4ac}$

(a) $x^2+4x+5=0\\D=4^2-4\cdot1\cdot5={-4}\\D$

D<0 means there are no real roots. there are two complex roots with imaginary components.

(b) D=16+20=36>0

D>0 means there are two real roots

D=0 means there is one real root with multiplicity 2

7 0

3 years ago