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3 years ago

15

Which system of linear inequalities is graphed below?

1 answer:

andrezito [222]3 years ago

6 0

Answer:

y > 2x - 1

y ≤ 0.5x + 4

Step-by-step explanation:

solid line: (0,4) (-8,0)

m: (0-4)/(-8-0) = -4/-8 = 0.5

b: 4

y = mx + b y = 0.5x + 4

dotted line: (0,-1) (-2,-5)

m = (-5 - -1)/(-2-0) = 2

b = -1

equation: y = 2x - 1

System: y ≤ 0.5x + 4

y > 2x - 1

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Which phrase represents' the sum of 11 and a number

denis23 [38]

Answer:

11 + n

Step-by-step explanation:

sum means addition, so u need a + sign

n is usually the variable used for 'a number'

so 11 and (+) a number (n) = 11+ n

hope this helps!

5 0

3 years ago

AB has endpoints at A(4,−8) and B(−6,−2).

lesantik [10]

(-2,-5) is the answer for this by doing -6-4 and -8–2

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4 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

4 years ago

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dedylja [7]

They are D. War Heroes!

3 0

3 years ago

C(n) = -7 + 6(n - 1) Find the 4^ term in the sequence.

Kay [80]

Answer: 11

Step-by-step explanation:

c(4)=-7+6(4-1)

c(4)= -7 + 6(3)

c(4)= -7 +18

c(4)= 11

3 0

3 years ago