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Lady_Fox [76]
4 years ago
12

AB has endpoints at A(4,−8) and B(−6,−2).

Mathematics
1 answer:
lesantik [10]4 years ago
6 0
(-2,-5) is the answer for this by doing -6-4 and -8–2
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BigorU [14]

Answer:

1. tan (4π/3) = √3

Answered by GAUTHMATH

5 0
3 years ago
Simplify the following radicals. 1. √16 2. √17 3. √18 4. √19 5. √20
Pavel [41]

Answer:

Step-by-step explanation:

1) \sqrt{16}= \sqrt{4*4}=4\\\\\\2)  \sqrt{17}

This is the simplest form as 17 is a prime number.

3)  \sqrt{18}= \sqrt{2*3*3} = 3 \sqrt{2}\\\\\\4) \sqrt{19}

19 is a prime number. so it is the simplest form.

5)  \sqrt{20}= \sqrt{2*2*5}=2 \sqrt{5}

3 0
3 years ago
Solve for x 5(x+1)=4(x+8)
joja [24]

Answer:

x=27

Step-by-step explanation:

expanding the above expression we get

5x+5=4x+32

grouping numbers with coefficient of x at the left side and constant at the right side we get

5x-4x=32-5

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8 0
3 years ago
Read 2 more answers
The hypotenuse of a right triangle is three times the length of one of its legs. The length of the other leg is four feet. Find
Elis [28]

Answer:

Step-by-step explanation:

Let the other leg = x

x^2 + 4^2 = (3x)^2

x^2 + 4^2 = 9x^2

4^2 = 9x^2 - x^2

16= 8x^2

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x = sqrt(2)

The lengths of the sides

x = sqrt(2)      

other side =4

hypotenuse = 3*sqrt(2)

x = 1.4

other side= 4

hypotenuse = 3*1.4142

hypotenuse = 4.2

4 0
3 years ago
Rewrite with only sin x and cos x. (6 points) cos 2x - sin x
velikii [3]

Answer:

The answer is a. cos2x - sin2x - sin x. Use the rule: cos2x = (cos^2)x - (sin^2)x. So, substitute cos2x in the expression: cos2x - sinx = ((cos^2)x - (sin^2)x) - sinx = (cos^2)x - (sin^2)x - sinx. Therefore, choice a. is correct choice.

4 0
3 years ago
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