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Lady_Fox [76]
3 years ago
12

AB has endpoints at A(4,−8) and B(−6,−2).

Mathematics
1 answer:
lesantik [10]3 years ago
6 0
(-2,-5) is the answer for this by doing -6-4 and -8–2
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Find m∠IUV if m∠IUV=x+49, m∠TUI=x+63, and m∠TUV=106∘.?<br> I'll mark you brainliest!
8090 [49]

Answer:

46

Step-by-step explanation:

You have to do IVU+TUI=TUV

so... x+49+x+63=106

5 0
3 years ago
The graph below shows three functions: Graph of function f of x equals 0.5 to the power x. Graph of function g of x is a line se
Phantasy [73]

Answer:   f(x)= 0.5^x has all real value as its domain.

Explanation: since, we have three functions f(x)=0.5^x,

while g(x) and p(x) are line segments.

Now, g(x) is a function by a line segment which passes through two points (-1.8,-3) and ( 1,3.8).

Thus it is clear that its domain will be the ends points. so domain of the function g(x) will be [-1.8, 3.8] which is the subset of real numbers set (R).

Similarly, domain of function p(x) will be [1.7, 1], which is also the subset of R.

But, when we talk about f(x) it contains all the possible value of x. Thus we can say that f(x)= 0.5^x has R as its domain.

8 0
3 years ago
Read 2 more answers
Solve the polynomial inequality x^2-3x-10&gt;0
djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0
3 years ago
ACTIVITY 1: What a Difference!
arsen [322]

Answer:

1. -2

2.-10

3. 16

4. -29

5. 3

6. 11

7. 3

8. -4

9. 14

10. 25

4 0
3 years ago
The first term in a sequence is 3<br> The term-to-term rule is + 8<br> What is the 5th term?
galben [10]
2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35


OR
((n-1)x8)+3
7 0
3 years ago
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