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vodka [1.7K]
3 years ago
15

5/9 (t +3) =40 PLSSS HELP MEEE

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Answer:

Step-by-step explanation:

Ok so T = 69

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Answer:

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Step-by-step explanation:

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Evaluate the six trigonometric functions of the angle 0.
Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

18^2 =10^2+\text{opposite}^2

324=100+\text{opposite}^2

Subtract 100 from both sides.

224=\text{opposite}^2

Taking square root on both sides.

4\sqrt{14}=\text{opposite}

Using trigonometric ratio formula:

$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}

$\sin\theta =\frac{4\sqrt{14} }{18}

$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}

$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

$\cos \theta=\frac{10}{18}

$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

$\sec \theta=\frac{18 }{10}

$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

8 0
3 years ago
Solve -5(8 – 0.5x) = -2(3 – 0.4x) HELP ASAP
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Answer:

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Step-by-step explanation:

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Answer:

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You have a 1-gallon paint can in the shape of a cylinder. One gallon is 231 cubic inches. The radius of the can is 3 inches. Wha
aleksandr82 [10.1K]

Answer:

The approximate height of the paint can is 8.2 in

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we know that

The volume of the cylinder ( can of paint) is equal to

V=\pi r^{2} h

we have

V=231\ in^{3}

r=3\ in

\pi=3.14

Substitute the values and solve for h

231=(3.14)(3)^{2} h

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