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Katyanochek1 [597]
3 years ago
6

Wendy buys a dress that costs $30.00 she pays 8% sales tax

Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

She pays $2.40 in sales tax

Step-by-step explanation:

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How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?
Makovka662 [10]

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! /  (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

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3 years ago
The frequency table shows the scores from rolling a dice.
bulgar [2K]

Answer:

3, 8

Step-by-step explanation:

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2 years ago
HELP PLEASE GIVING BRAINLIST TO ANYONE WHO ANSWERS
stira [4]

Answer:

7.5

Step-by-step explanation:

SInce 11x-17 is a corrosponding angle to 65, we can make an equation with them.

11x-17=65

Carry over the 17 (add to both sides)

11x= 82

divide 82 by 11

x=7.5

(the answer kept repeating so i rounded it to the nearest tenth)

Hope this helps :)

5 0
2 years ago
Jay's mother bought a rectangular rug for the dining room. The dimensions of the rug are 4 yards by 3 yards. Which is the correc
Tasya [4]
The answer will be B. Hope it help!
5 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words.
lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17   eq(1)

y = -1/2x            eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 5/4, b =0 and c = -17

x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}

Finding value of y:

y = -1/2x

y=-1/2(\frac{\pm2\sqrt{85}}{5})

y=\frac{\pm\sqrt{85}}{5}

System A has 4 real solutions.

System B

y = x^2 -7x + 10    eq(1)

y = -6x + 5            eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-1 and c =5

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9    eq(1)

8x - y = -17        eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17    

8(-2) - y = -17    

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0
3 years ago
Read 2 more answers
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