The correct answers are as follows:
1. A.
There are basically two types of succession, they are primary and secondary succession. Primary succession refers to the type of succession that occurs in new and bare areas where the soil present is unable to sustain the growth of plants. An example of primary succession area is an area with sand dunes that is freshly formed. Primary succession usually occur over a long period of time. Secondary succession is a type of succession that occur on a land which was disturbed by hazardous events such as fire outbreak, flood, etc. Secondary succession occurs much faster than the primary succession.
2. D
There are two types of factors that affect any particular ecosystem, these are abiotic and biotic factors. The abiotic factors refers to non living factors such as temperature, relative humidity, rainfall, etc. while the biotic factors refer to the living factors. Looking at the options given above, one will see that only option D has living factor, which is predators. All other options have abiotic factors.
<span>The propositions are:
a. forms glucose from </span><span>noncarbohydrates
b. does all of these
c. destroys damaged red blood cells
d. stores vitamin D
e. forms urea
The right answer is: B. </span>does all of these
*The liver plays a role in the metabolism of carbohydrates:- gluconeogenesis (manufacture of a new glucose molecule from a non-carbohydrate molecule);- glycogenolysis (release of glucose from glycogen) under the effect of glucagon;- gluconeogenesis (storage of glucose in the form of glycogen) under the effect of insulin
*It stores fat-soluble vitamins (A, D, K and E) and glycogen.*It converts ammonia to urea (detoxification)<span>*It recycles substances from the senescent red blood cells.</span>
Answer:
Most fish use gills for gas exchange instead of lungs.
Explanation:
Answer:
F (pp) = 0.04
F (Pp) = 0.32
F (PP) = 0.64
Explanation:
Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.
If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.
This means that 0.04 corresponds to p², and p corresponds to 0.2.
Therefore, P is equal to 0.8 because p + P = 1.
Knowing the allele frequencies, we go to the frequency of the genotypes.
F (pp) = p² = 0.04 = 8 snails
F (Pp) = 2.Pp = 0.32 = 64 snails
F (PP) = P² = 0.64 = 128 snails
