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3 years ago

The moon forms a right triangle with the Earth and the Sun during one of its phases, as shown below:

Mathematics

1 answer:

nordsb [41]3 years ago

7 0

Answer:

Step-by-step explanation:

The Earth, Sun and Moon form a right triangle.

By the definition of cosine in a right triangle we can write that

cos x ° = adjacent side /hypothenuse = y/ distance Moon Sun

Since we measured the angle x, and the distance y we can use algebra to find the unknown distance between the moon and the Sun.

distance Moon Sun = y/cos x°

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Name all sets of number for -15

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Answer:

all negative number to -15

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What is the product of 6x – y and 2x – y + 2? 8x2 – 4xy + 12x + y2 – 2y 12x2 – 8xy + 12x + y2 – 2y 8x2 + 4xy + 4x + y2 – 2y 12x2

ella [17]

Answer:

Product of two expression is $(6x-y)(2x-y)=12x^2-8xy+y^2$

Step-by-step explanation:

Given : Expression - $6x- y$ and $2x-y$

To find : The product of given expression

Solution : To find the product we apply distributive law

$a(b+c)=ab+ac$

We write in the form of product and multiply term by term

$(6x-y)(2x-y)$

$=(6x)(2x-y)-y(2x-y)$

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$=(6x)(2x)-(6x)(y)-y(2x)+(y)(y)$

$=12x^2-6xy-2xy+y^2$

$=12x^2-8xy+y^2$

Therefore, Product of two expression is $(6x-y)(2x-y)=12x^2-8xy+y^2$

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3 years ago

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3 years ago

Simplify the surd 3√ 20 +√ 45

melisa1 [442]

Answer:

9 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify the radicals

$\sqrt{20}$

= $\sqrt{4(5)}$

= $\sqrt{4}$ × $\sqrt{5}$

= 2 $\sqrt{5}$

$\sqrt{45}$

= $\sqrt{9(5)}$

= $\sqrt{9}$ × $\sqrt{5}$

= 3 $\sqrt{5}$

Then

3 $\sqrt{20}$ + $\sqrt{45}$

= 3(2 $\sqrt{5}$ ) + 3 $\sqrt{5}$

= 6 $\sqrt{5}$ + 3 $\sqrt{5}$

= 9 $\sqrt{5}$

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3 years ago

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skelet666 [1.2K]

Answer:

the answer is 4x $10^{2}$

Step-by-step explanation:

I hope this helps

have a nice day/night

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3 years ago

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