"1 indicating a coupon and all other outcomes indicating no coupon"
Probability is (number of successful outcomes) / (number of possible outcomes)
Theoretical Probability of rolling a 1: 1/8
Experimental Probability of using coupons: 4/48 = 1/12
So, the experimental probability of a customer using a coupon (that is, 1/12) is smaller than the theoretical probability of rolling a 1 (that is, 1/8).
Answer:
42x^2
Step-by-step explanation:

Using concepts of <u>sample and population</u>, it is found that the sample variance is representative of 362 and 5530 customers ages, option D.
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In sampling, the <u>information is taken from a sample</u>, and is used to <u>estimate it for the whole population</u>.
- In this problem, we have a sample of 362 and a population of 5530 customers.
- The sample variance
is calculated from the sample, and used as an estimate for the population variance. Thus, it can be said that it represents both 362 and 5530 customers, and the correct option is D.
A similar problem is given at brainly.com/question/4086221
Answer: (3) f(8) = g(8)
<u>Step-by-step explanation:</u>
Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4
<u> f(x) </u> <u> g(x) </u> <u>Comparison</u>
f(x) = 2x - 3 
f(0) = 2(0) - 3 
= -3 = 1 f(0) < g(0)
f(2) = 2(2) - 3 
= 1 = 4 f(2) < g(2)
f(8) = 2(8) - 3 
= 13 = 13 f(8) = g(8)
f(4) = 2(4) - 3 
= 5 = 7 f(4) < g(4)
The only statement provided that is true is f(8) = g(8)
Circumference of a circle = 2pir
2pi(5) = 10pi