Answer:
The answer was graph 2
Step-by-step explanation:
I am horrible at explaining but this is the answer
Answer:
The actual speed of the car is either 57 mph or 63 mph
Step-by-step explanation:
Given as :
The measured speed o the car = 60 mph
The percentage error in speedometer = 5 %
Let The actual speed of car = x mph
Now, percentage error =
× 100
So,
= 
or,
× 60 = x - 60
Or, 3 = x - 60
∴ x = 63 mph
Hence The actual speed of the car is either 57 mph or 63 mph . Answer
The group paid $ 5250 at first city and $ 6250 at second city
<u>Solution:</u>
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
The hotel charge before tax in the second city was $1000 higher than in the first
Then the charge at the second hotel before tax will be x + 1000
y = x + 1000 ----- eqn 1
The tax in the first city was 8.5% and the tax in the second city was 5.5%
The total hotel tax paid for the two cities was $790
<em><u>Therefore, a equation is framed as:</u></em>
8.5 % of x + 5.5 % of y = 790

0.085x + 0.055y = 790 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.085x + 0.055(x + 1000) = 790
0.085x + 0.055x + 55 = 790
0.14x = 790 - 55
0.14x = 735
<h3>x = 5250</h3>
<em><u>Substitute x = 5250 in eqn 1</u></em>
y = 5250 + 1000
<h3>y = 6250</h3>
Thus the group paid $ 5250 at first city and $ 6250 at second city
Step-by-step explanation:
after 60% reduction he paid 40% of its price=224

224×100=40×?
?=560