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zmey [24]
3 years ago
14

What is the solution to the division problem below x^3-x^2-11x+3/ x+3

Mathematics
1 answer:
evablogger [386]3 years ago
3 0
I believe the answer is x^2-4x+1

(I did the problem in my head but it seems correct)
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Your class is selling wrapping paper and candles. Rolls of paper sell for $7 and candles sell for $10 each. A total of 109 items
Klio2033 [76]

Answer:

53 Rolls of paper and 56 Candles

Step-by-step explanation:

56 x $10 = $560

$7 x 53 = $371

$560 + $371 = $931

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Diano4ka-milaya [45]
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Please help!!<br> Each pair of polygons is similar. Find the value of x.
Simora [160]

Answer in fraction form: x = 55/4

Answer in decimal form: x = 13.75

Both forms are equivalent, but they say it in a slightly different way.

===========================================================

Work Shown:

AC/QY = CD/YW

(x+5)/15 = 5/4

4(x+5) = 15*5

4x+20 = 75

4x = 75-20

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x = 55/4

x = 13.75

------------

Explanations:

  • The first step is possible because the polygons are similar. Similar figures have their corresponding sides be in the same proportion or ratio. Note how side AC has the double red angle (at point A) and a single red angle (point C). The side QY has the same idea in the same order. This is why AC corresponds to QY. The ratio AC/QY is the same as CD/YW.
  • In the second step, I plugged in the expressions that the diagram shows. This is the substitution property.
  • On step 3, I cross multiplied. The general format is A/B = C/D cross multiplies to A*D = B*C.
7 0
3 years ago
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julsineya [31]

Answer:

16g

Step-by-step explanation:

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The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are
arsen [322]

Answer:

  16 cm^2 and 49 cm^2

Step-by-step explanation:

The ratio of areas is the square of the ratio of linear dimensions, so is ...

  (4/7)^2 = 16/49

The sum of these "ratio units" is 16 +49 = 65. The sum of triangle areas is 65 cm^2, so each "ratio unit" must stand for 1 cm^2 of area. That is, the triangles must have areas of ...

  • 16 cm^2
  • 49 cm^2
3 0
3 years ago
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