I'm pretty sure this is correct
Where did paco make an error in his calculation?Explain.
1 answer:
You might be interested in
Let
F--------> represent the force
m--------> represent the mass
a-------> represent the acceleration
we know that
The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to
<u>Part a)</u> Solve this equation for a
Divide both sides by the mass
therefore
<u>the answer part a) is equal to</u>
<u>Part b) </u>Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?
we know that
the formula of acceleration is equal to
in this problem
we have
Substitute the values n the formula
therefore
<u>the answer part b( is equal to</u>
<u>Part c)</u> Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?
we know that
Solve for m
Divide both sides by the acceleration
in this problem
we have
Substitute the values n the formula
therefore
<u>the answer Part c) is </u>
Answer:
2) D: x = [0, 24]
3) R: y = [0, 384]
4) see graph
<u>Step-by-step explanation:</u>
Eric's regular wage is $12 per hour for all hours less than 9 hours.
The minimum number of hours Eric can work each day is 0.
f(x) = 12x for 0 ≤ x < 9
Eric's overtime wage is $18 per hour for 9 hours and greater.
The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).
f(x) = 18(x - 8) + 12(8)
= 18x - 144 + 96
= 18x - 48 for 9 ≤ x ≤ 24
The daily wage where x represents the number of hours worked can be displayed in function format as follows:
2) Domain represents the x-values (number of hours Eric can work).
The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.
D: 0 ≤ x ≤ 24 → D: x = [0, 24]
3) Range represents the y-values (wage Eric will earn).
Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.
The minimum hours he can work in one day is 0.
f(x) = 12x
f(0) = 12(0)
= 0
The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>
f(x) = 18x - 48
f(24) = 18(24) - 48
= 432 - 48
= 384
D: 0 ≤ y ≤ 384 → D: x = [0, 384]
4) see graph.
Notice that there is an open dot at x = 9 for f(x) = 12x
and a closed dot at x = 9 for f(x) = 18x - 48
