WILL GIVE EXTRA POINTS Assignment name: Segment Addition

Solve: log (7t + 2) = 2 t =

IrinaK [193]

Answer:

t = 14

Step-by-step explanation:

log (7t + 2) = 2

Raise each side to the power of 10

10 ^log (7t + 2) =10^ 2

7t+2 = 100

Subtract 2 from each side

7t+2-2 = 100-2

7t = 98

Divide each side by 7

7t/7 = 98/7

t = 14

7 0

4 years ago

Read 2 more answers

Jason knows that the equation to calculate the period of a simple pendulum is , where T is the period, L is the length of the ro

Brrunno [24]

Answer-

$\boxed{\boxed{L=\dfrac{g}{4\pi^2 f^2}}}$

Solution-

The equation for time period of a simple pendulum is given by,

$T=2\pi \sqrt{\dfrac{L}{g}}$

Where,

T = Time period,

L = Length of the rod,

g = Acceleration due to gravity.

Frequency (f) of the pendulum is the reciprocal of its period, i.e

$f=\dfrac{1}{T}\ \Rightarrow T=\dfrac{1}{f}$

Putting the values,

$\Rightarrow \dfrac{1}{f}=2\pi \sqrt{\dfrac{L}{g}}$

$\Rightarrow (\dfrac{1}{f})^2=(2\pi \sqrt{\dfrac{L}{g}})^2$

$\Rightarrow \dfrac{1}{f^2}=4\pi^2 \dfrac{L}{g}$

$\Rightarrow L=\dfrac{g}{4\pi^2 f^2}$

8 0

4 years ago

Read 2 more answers

On the first visit to the veterinarians office chorus kitten weighed 550 g on the second visit the kitten had ganged 350 g on th

Roman55 [17]

Answer:

$\%Increase = 118\%$

Step-by-step explanation:

Given

$Initial\ Weight = 550g$

$First\ Addition = 350g$

$Second\ Addition = 300g$

Required

Determine the percentage increment

First, we have to calculate the new weight

$New\ Weight = Initial\ Weight + First\ Addition + Second\ Addition$

$New\ Weight = 550g + 350g + 300g$

$New\ Weight = 1200$

The percentage increment is then calculated as:

$\%Increase = \frac{New\ Weight - Initial\ Weight}{Initial\ Weight} * 100\%$

$\%Increase = \frac{1200g - 550g}{550g} * 100\%$

$\%Increase = \frac{650g}{550g} * 100\%$

$\%Increase = \frac{650}{550} * 100\%$

$\%Increase = 1.182* 100\%$

$\%Increase = 118.2\%$

$\%Increase = 118\%$ -- Approximated

Hence, the percentage increment is approximately 118%

6 0

3 years ago

The volume of the capsule

STatiana [176]

Volume of cylinder
πr^2h
π6^2x11=396π

Volume of sphere
4/3πr^3
4/3π6^3=288π

396π+288π=684π
=2148.849375

7 0

4 years ago

Please solve y=x^2-6x-5 by factoring and by using the quadratic formula with work attached

Lynna [10]

Factoring:

This equation cannot be factored because its roots are irrational (as shown by solving with the quadratic formula). Also, to factor a quadratic equation, you need to find a pair of numbers whose product is equal to the c term (-5) and whose sum is equal to the b term (-6). There is no pair of numbers which satisfies this, further showing that the equation cannot be factored.

Quadratic Formula:

The quadratic formula is x= $\frac{-b ± \sqrt{b^{2}-4ac } }{2a}$ .

First, you need to find the a, b and c terms of your equation. They are 1, -6, and -5 respectively.

Now, you must plug in to the equation and solve for x. You must do so twice, once with a plus sign in the numerator and once with a minus.

$\frac{6 ± \sqrt{(-6)^{2}-4(1)(-5) } }{2(1)} \\\frac{6 ± \sqrt{36+20} }{2} \\\frac{6 ± \sqrt{56} }{2} \\\ \frac{6 ± 2\sqrt{14} }{2} \\3+\sqrt{14} \\3-\sqrt{14}$

The answers are 3+√14 and 3-√14.

Hope this helps!!

3 0

3 years ago

WILL GIVE EXTRA POINTSAssignment name: Segment Addition ​

WILL GIVE EXTRA POINTSAssignment name: Segment Addition