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sdas [7]
3 years ago
10

Factor the expression. 6x^2 + 5x + 1

Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0

Answer: C

Step-by-step explanation: Answer is C

Whitepunk [10]3 years ago
6 0

Answer:

Option C

Step-by-step explanation:

6x² +5x + 1

6x² + 3x + 2x + 1

3x(2x + 1) + 1(2x + 1)

(3x + 1)(2x + 1)

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Sean bought a 6 inch sub. He ate 3 3/4 inches. How much sub does he have left in the simplest form.
irinina [24]

Answer: 2 1/2

hope this helps

4 0
3 years ago
∆DEF≈~ STU. If TU-=8, SU = 10, and ST= 4, what is the length of -DE-?
Morgarella [4.7K]

Answer:

if that statement is true, then DE=ST, and ST=4 so your answer should be <u>DE=4</u>

Explanation:

you can tell that they are even from looking at the first statement, it states <u>DE</u>F=<u>ST</u>U, emphasizing on the DE=ST part, it gives your the answer right there because ST=4

3 0
2 years ago
Read 2 more answers
27 + (8-5) -am looking for the answer of number 7
Rasek [7]

Answer:

The answer to the equation from question 7 is 14.

Step-by-step explanation:

In question 7, we are given an equation.

2³ + (8 - 5)² - 3

First, subtract 5 from 8 in the parentheses.

2³ + 3² - 3

Next, solve the exponents for 2³ and 3².

8 + 9 - 3

Add 8 to 9.

17 - 3

Subtract 3 from 17.

14

So, the answer to this equation from question 7 is 14.

4 0
3 years ago
Please help me thank youuu
zhuklara [117]

Answer:

m<Q = 133°

Step-by-step explanation:

From the question given above, the following data were obtained:

m<P = (x + 13)°

m<Q = (10x + 13)°

m<R = (2x – 2)°

m<Q =?

Next, we shall determine the value of x. This can be obtained as follow:

m<P + m<Q + m<R = 180 (sum of angles in a triangle)

(x + 13)° + (10x + 13)° + (2x – 2)° = 180

x + 13 + 10x + 13 + 2x – 2 = 180

x + 10x + 2x + 13 + 13 – 2 = 180

13x + 24 = 180

Collect like terms

13x = 180 – 24

13x = 156

Divide both side by 13

x = 156 / 13

x = 12

Finally, we shall determine m<Q. This can be obtained as follow:

m<Q = (10x + 13)°

x = 12

m<Q = 10(12) + 13

m<Q = 120 + 13

m<Q = 133°

8 0
3 years ago
How do you solve quadratic equations?
masha68 [24]
In any equation there is a variable (usually x). In a quadratic equation there is a lot involved.

-B (+or-) sqrt of b^2 - 4 x A x C
________________________  divide it by
               2 x A
                                                   There is usually an original equation that looks like:  Ax^2 + Bx + C = 0    Use the variables from the equation to the left to fill the upper equation.  (You can also look up a better formula if confused).

8 0
3 years ago
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