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Natali [406]
3 years ago
13

Answer for branliest and friend request

Mathematics
2 answers:
Gelneren [198K]3 years ago
6 0

Answer:

I'm pretty sure the answer is C

Step-by-step explanation:

I hope this helps! please mark as branliest

Lubov Fominskaja [6]3 years ago
5 0

Answer:

the answer is c: 0.5 x 0.2= 0.1

Step-by-step explanation:

I worked it out and got it right.

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The diagram represents 6x^2-7x+2with the factor of 2x-1. What is the factor of 6 x^2-7x+2
Maksim231197 [3]

Answer:

(6x²-7x+2)/2x-1

(2x-1)(3x-2)/2x-1

=

<h2>3x-2</h2>
5 0
3 years ago
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How many solutions does this system of linear equations have? Explain. 3y + 6x = 12 8x + 4y = 16
Vilka [71]

Answer:

first equation : 3y + 6×=12

second equation : 4y + 8x = 16

Step-by-step explanation:

first equation

3y + 6× = 12

now take the common ,

3( y + 2x ) = 12

so, y + 2x = 4

second equation

4y + 8x = 16

4 ( y + 2x ) = 16

so, y + 2x = 4

two lines with same equation have infinitely many solution . these two equations are the same so there are infinitely many solution .

3 0
3 years ago
Erin spent $15.30 on ingredients for cookies she’s making for the school bake sale. How many cookies must she sell at $0.35 a pi
blondinia [14]

Answer:

she needs to sell at least 44 cookies to make a $0.10 profit

Step-by-step explanation:

to find the answer all you have to do is divide 15.30 by 0.35

4 0
3 years ago
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Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0
Black_prince [1.1K]

Answer:

x = pi, 3pi, 5pi  etc

x = -pi, -3pi, -5pi etc

Step-by-step explanation:

cos^2 x + 2 cos x + 1 = 0

replace cos x with m

m^2 + 2m +1 = 0

solve by factoring  (this is a^2 +2ab+b^2 = (a+b)^2  where a =m and b=1)

(m+1)^2=0

take the square root of each side

m+1 =0

m=-1

now replace m with cos x

cos x = -1

take arccos  of each side

arccos cos x = arccos (-1)

x = pi, 3pi, 5pi  etc


3 0
3 years ago
I’m really confused please help
Vikentia [17]

Answer:

(2). <em>b - (a + c)i </em>

Step-by-step explanation:

i^{7} = [( i )²]³ × i = ( - 1)³ i = - i

i^{16} = ((i)^2)^{8} = ( - 1)^{8} = 1

((i)^2)^{10} × i = i

a(- i ) + b( 1 ) - c( i ) = - ai + b - ci = <em>b - (a + c)i</em>

4 0
3 years ago
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