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yulyashka [42]
3 years ago
12

Find The sum of the first 10 terms 8,20,32,44

Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

Answer:

S₁₀=620

Step-by-step explanation:

This is an arithmetic sequence with a common difference of d=12

The formula for an arithmetic series is Sₙ=(n/2)(a₁+aₙ) where aₙ is the nth term and a₁ is the first term.

We know that a₁=8 and d=12 where the 10th term would be a₁₀=8+(10-1)12=116.

Therefore, the sum of the first 10 terms of the arithmetic series is S₁₀=(10/2)(8+116)=(5)(124)=620

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8 0
3 years ago
Which of the following is an odd function?
Komok [63]

Given:

f(x)=x^{3}+5 x^{2}+x

f(x)=\sqrt{x}

f(x)=x^{2}+x

f(x)=-x

To find:

The odd function.

Solution:

If f(-x) = -f(x), then the function is odd.

If f(-x) = f(x), then the function is even.

Option A: f(x)=x^{3}+5 x^{2}+x

Substitute x = -x

f(-x)=(-x)^{3}+5 (-x)^{2}+(-x)

          =-x^3+5x^2-x

          =-(x^3-5x^2+x)

          ≠ - f(x)

It is not odd function.

Option B: f(x)=\sqrt{x}

Substitute x = -x

f(-x)=\sqrt{-x}

          =\sqrt{x} i   (Since \sqrt{-1} =i)

          ≠ - f(x)

It is not odd function.

Option C: f(x)=x^{2}+x

Substitute x = -x

f(-x)=(-x)^{2}+(-x)

          =x^2-x

          =-(-x^2+x)

          ≠ - f(x)

It is not odd function.

Option D: f(x)=-x

Substitute x = -x

f(-x)=-(-x)

          =-f(x)

It is odd function.

Therefore, f(x) = -x is an odd function.

5 0
3 years ago
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Answer:

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Step-by-step explanation:

Very simple, Keep It, Change It, Flip it

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3 years ago
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Answer:

100

Step-by-step explanation:

it is C

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

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792+678.24=1470.24

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3 years ago
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