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3 years ago

Can someone please help me?

Mathematics

1 answer:

Alisiya [41]3 years ago

5 0

Answer:

(x+3)(x-3)(x+1)

Step-by-step explanation:

Look it up on y ou tbe

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52.7 × 12= ?<br><br>help again huhuhu

lyudmila [28]

Answer:

632.4

Step-by-step explanation:

4 0

2 years ago

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6 is a factor of 2 true or false

m_a_m_a [10]

False. 2 is a factor of 6.

5 0

3 years ago

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Use logarithmic differentiation to find dy/dx

liq [111]

Answer:

dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]

Step-by-step explanation:

y = (x^2 - 3)^sinx

ln y = ln (x^2 - 3)^sinx

ln y = sin x * ln (x^2 - 3)

1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x

1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)

dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y

dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]

7 0

3 years ago

Are 2.8 and 2.800 equal? PLEASE HELP THIS IS DUE TOMMORROW!

lutik1710 [3]

They are the zeros have no meaning

8 0

3 years ago

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Silas had 3 times as much money as Raja. Silas spent $84 of his money to buy a birthday gift for his grandma while Raja was awar

Tamiku [17]

Answer:

Total amount Silas and Raja has at first = $252

Step-by-step explanation:

Let,

Amount Silas had = x

Amount Raja had = y

According to given statement;

x = 3y Eqn 1

x-84 = y+42 Eqn 2

Putting value of x from Eqn 1 in Eqn 2

3y - 84 = y+42

3y-y = 42+84

2y = 126

Dividing both sides by 2

$\frac{2y}{2}=\frac{126}{2}\\y=63$

Putting y = 63 in Eqn 1

x = 63(3)

x = 189

Total amount they had = 189 + 63 = $252

Hence,

Total amount Silas and Raja has at first = $252

8 0

2 years ago