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jeyben [28]
2 years ago
5

Aarons wrestling coach played him in the highest weight class all the wrestlers and the weight class away at least 115 lb if w s

tanding for Aarons weight which and inequality represents his current weight??​
Mathematics
1 answer:
Alika [10]2 years ago
3 0

Answer:

Step-by-step explanation:

sorry to bother you but if you see a guy called breedall and sends you a sketchy link dont click it because its a virus on your computer

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Weights of newborn babies are normally distributed with a mean of 7.452 pounds and
patriot [66]

Answer:

21

Step-by-step explanation:

8 0
2 years ago
F(x) = x2 – 2x - 8
maw [93]

Answer:

The y-intercept is the point (0,-8)

see the attached figure

Step-by-step explanation:

we have

f(x)=x^{2}-2x-8

we know that

The y-intercept is the value of the function f(x) when the value of x is equal to zero

so

For x=0

f(x)=0^{2}-2(0)-8\\f(x)=-8

therefore

The y-intercept is the point (0,-8)

see the attached figure to better understand the problem

5 0
3 years ago
What’s the answer the multiple choice is there to please don’t guess
Anit [1.1K]
<h3>Answer: Point E is located at (2, 3)</h3>

====================================

Explanation:

The sequence PQRST has T as the last letter.

The sequence ABCDE has E as the last letter

The two letters T and E pair up or they correspond. So T will rotate to land on point E. Or T will rotate to point E's location.

Point T is at location (-3,2). So x = -3 and y = 2.

-------

Use the rule

(x,y) ---> (y, -x)

which is the rule we use when we rotate any point 90 degrees clockwise around the origin. We swap the x and y coordinates, then change the sign of the second coordinate (after the swap happens).

This means,

(-3, 2) ----> (2, -(-3)) = (2, 3)

or simply

(-3, 2) ---> (2, 3)

6 0
3 years ago
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
2 years ago
Okay how do I reach out to Katie. I'm gonna scream-. I have stopped answering questions for this reason and they still delete my
Vesna [10]

Answer:

You can't she do the same thing to me like I just be answering question for points and they mostly be correct and she just be deleting the questions like crazy.

3 0
2 years ago
Read 2 more answers
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