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RUDIKE [14]
3 years ago
9

Find the greiple ofR(x) =( x ^3+10x^2 +32x+32)÷(X^2 + 2x-15)​

Mathematics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

x3(+10x2 +32x +32) / (2 +30)

Step-by-step explanation:

(x3 +10x2 + 32x +32) / (x2 + 2 * 15)

x3(+10x2 +32x +32) / (2 +30)

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Answer:

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svetoff [14.1K]

Step-by-step explanation:

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Please help me with question 2
WARRIOR [948]

Answer:

sin(-a)= -15 /17

Step-by-step explanation:

Alright, lets remember that sin(x) is odd function, which means that

wherever you watch an expression like this: sin(-a), you can use the odd functions property, and turn it like the following

sin(-a)= - sin(a)

Now, other thing to remember: (sin(x))^{2}+(cos(x))^{2}=1

So, we can obtain any value for sin(x) function starting from the opposite function, cos(x), using the following:

sin(x)=\sqrt{1-(cos(x))^{2} }

So, if cos(a)= - 8 / 17, using the above equation we obtain the value for sin(a)

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