1) Consider the departure point is A (0,0).
After one hour flight with an angle of elevation of 10°, it travelled a distance of 550 mi. (speed 550 mi/h) and reached an altitude of H.
(Imagine a right triangle: Departure point A (0,0), with angle of elevation A= 10° and after one hour reaching a point B, at an altitude H, note that AB = hypotenuse-)
Let's calculate H (after 1 hour/flight)
sin10° = H/AB = H/550 and H= 95.5065 mi, Speed of H = 95.506 mi/h
2) The shadow is represented by the horizontal side, adjacent to 10°.
So when the plane is advancing at 550 mi/h, the shadow is stretched at a speed S.
Now let's calculate the length of the shadow (always after one hour flight)
Pythagoras: 550² =95.5065² +(length of shadow)²
And Length of shadow = 541.65 mi
S= 541.65/1 hour = 541.65 mi/h
Answer:
your answer is 40 percent
Step-by-step explanation:
can i get brainly
Answer:
1. >
2.>
3.<
4. <
Step-by-step explanation:
I am doing it from top to bottom
I hope this helps! :)
Answer:
b
Step-by-step explanation:
its 7x4 bc if you count the blocks on the lenghth its 7 and the side is 4
Answer:
Apothem = 3.3 units
Step-by-step explanation:
A regular nonagon has an area of 102.4 and one side length measures 7 units long. Find the apothem. Round to the nearest tenth, if necessary.
The formula to find the area of a polygon when given Apothem and Side length =
A = 1/2 × a × p
Where p = no of sides of polygon × side length
In the above question,
We are given a polygon = nonagon = 9 sides
Side length = 7 units
p = 9 × 7 = 63 units
Area = 102.4 square units
Apothem = a = ?
We substitute into the formula
102.4 = 1/2 × a × 63
102.4 = 63a/2
Cross Multiply
102.4 × 2 = 63a
Divide both sides by 63
a = 102.4 × 2/63
a = 3.2507936508 units
Approximately to the nearest tenth = 3.3 units