X^2+7x-8>0 eliminating denominator
Factoring (x+8)(x-1) must be positive so
Case 1 both positive is x>-8 and x>1. For both to occur x>1
Case 2 both are negative (x+8)<0 and (x-1)<0 so x<-8 and x<1. For both to occur x<-8
Therefore x<-8 or x>1
Answer:
<h2>A, C</h2>
Step-by-step explanation:
The distributive property:
<em>a(b + c) = ab + ac </em>or<em> a(b - c) = ab - ac</em>
<em></em>


X - 15 > 2x + 8 (I'm 99%) sure that is the answer
A triangle does have 3 sides, so this statement is a true statement/a fact
Step-by-step explanation:
u vector components:
x-comp = 8 - (-17) = 25
x-comp = -11 - 4 = -15
Therefore, we can write vector u as
u = 25i - 15j
v = 14i - 4j
u - v = 11i - 11j
Therefore,
2(u - v) = 22i - 22j