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AnnZ [28]
3 years ago
11

A tanker company has

Mathematics
1 answer:
sergejj [24]3 years ago
3 0

Answer:

c

Step-by-step explanation:

107 x 3.778 x 125/100 = 4.735 x 1-7

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The arena set-up team’s work schedule is shown in the table below. Convert the minutes worked into hours.
Sladkaya [172]

Answer:

Mike\ Chewer = 14\frac{1}{2}\ hr

Jennifer\ Glass = 3\frac{3}{4}\ hr

Fred\ Carlton = 1\frac{1}{4}\ hr

Amy\ Amaretto = 12\ hr

Step-by-step explanation:

Given

Mike\ Chewer = 870\ minutes

Jennifer\ Glass = 225\ minutes

Fred\ Carlton = 75\ minutes\\

Amy\ Amaretto = 720\  minutes

Required

Convert to hours (in fraction)

To do this, we simply divide the time by 60

Mike\ Chewer = 870\ minutes

Divide by 60

Mike\ Chewer = \frac{870}{60}\ hr

Mike\ Chewer = \frac{87}{6}\ hr

Express as mixed numbers

Mike\ Chewer = 14\frac{3}{6}\ hr

Simplify

Mike\ Chewer = 14\frac{1}{2}\ hr

Jennifer\ Glass = 225\ minutes

Divide by 60

Jennifer\ Glass = \frac{225}{60}\ hr

Express as mixed numbers

Jennifer\ Glass = 3\frac{45}{60}\ hr

Simplify

Jennifer\ Glass = 3\frac{3}{4}\ hr

Fred\ Carlton = 75\ minutes\\

Divide by 60

Fred\ Carlton = \frac{75}{60}\ hr

Express as mixed numbers

Fred\ Carlton = 1\frac{15}{60}\ hr

Simplify

Fred\ Carlton = 1\frac{1}{4}\ hr

Amy\ Amaretto = 720\  minutes

Divide by 60

Amy\ Amaretto = \frac{720}{60}\ hr

Amy\ Amaretto = 12\ hr

3 0
3 years ago
A certain type of automobile battery is known to last an average of 1110 days with a standard deviation of 50 days. If 100 of th
GalinKa [24]

Answer:

a. P(1104<X[bar]<1110) =  0.3849

b. P(X[bar]>1116) = 0.1151

c. P(X[bar]<940) = 0

Step-by-step explanation:

Hello!

Your study variable is X: "length of life of a battery" (days)

These batteries have a known lifetime average μ: 1110 days and a standard deviation δ:50 days.

To calculate the probabilities I'll apply the Central Limit Theorem, and since the sample is big enough (n>30), approximate the distribution of the sample mean to normal X[bar]≈N(μ;δ²/n) and use the standardization to the Z-distribution to calculate each probability.

a. The average is between 1104 and 1110

P(1104<X[bar]<1110) = P(X[bar]<1110) - P(X[bar]<1104)

= P(Z<(1110-1110)/(50/√100) - P(Z<(1104-1110)/(50/√100))

=P(Z<0) - P(Z<-1.2) = 0.5 - 0.1151 = 0.3849

b. The average is greater than 1116

P(X[bar]>1116) = 1 - P(X[bar]≤1116) = 1 - P(Z≤(1116-1110)/(50/√100))

=1 - P(Z≤1.2) = 1 - 0.8849 = 0.1151

Since the Z table accumulates from left, this means, the probability values it gives are P(Z), to calculate the values ​​above a certain number, you have to subtract from 1 (the highest possible cumulative probability value) all the cumulative probability that is below that number.

c. The average is less than 940.

P(X[bar]<940) = P(Z<(940-1110)/(50/√100)) = P(Z<-34) = 0

I hope you have a SUPER day!

5 0
3 years ago
Seraph in is comparing the graphs of the parent function y = x^2 and the function y = 6(x − 3)^2 − 8. He makes the following sta
Y_Kistochka [10]

Answer:

A. No; Seraphin's first statement is not correct. Because the a-value is positive, the graph should be stretched horizontally by a factor of 6.

Step-by-step explanation:

5 0
3 years ago
Find (3 × 104) + (7 × 102). A) 3.07 × 102 Eliminate B) 3.07 × 104 C) 3.70 × 102 D) 3.70 × 104
Goryan [66]
Nice and simple. PEMDAS. Parentheses, exponents, multiple, division, addiction, subtraction.

The first thing you do is solve the numbers in the parenthesis, which would turn to 

(312) + (714) = 1026
6 0
3 years ago
Read 2 more answers
45. Real Estate Appreciation Bob Michaels purchased a
Tju [1.3M]

Answer:

a)

Since t is between 0 and 15, and the house was purchased 8 years ago, we have two pairs of values:

  • t = 0, V(0) = 42000
  • t = 8, V(8) = 67500

<u>Find the slope, m:</u>

  • m = (67500 - 42000)/8 = 3187.50

The value of b is 42000, since at t = 0, V = 42000

<u>So the equation is:</u>

  • V = 3187.50t + 42000

b)

The graph is attached.

When V = 72500, t = 9.6 (approximately)

c)

When V = 74000

  • 74000 = 3187.5t + 42000
  • 3187.5t = 32000
  • t = 32000/3187.5
  • t ≈ 10 years (rounded down)

d)

When V = 80250

  • 80250 = 3187.5t + 42000
  • 3187.5t = 80250 - 42000
  • 3187.5t = 38250
  • t = 38250/3187.5
  • t = 12 years

4 0
3 years ago
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