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Musya8 [376]
3 years ago
14

I need help with this problem y=5x-3

Mathematics
1 answer:
defon3 years ago
3 0

Answer:

Slope= 5

y intercept= (0,-3)

Step-by-step explanation:

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8 0
3 years ago
What is the radius of a circle given by the equation x2 + y2 – 2x + 8y – 47= 0? radius = units
il63 [147K]
ANSWER

The radius is 8

EXPLANATION

We were given,

{x}^{2}  +  {y}^{2}  - 2x + 8y - 47 = 0




We rewrite the above equation to obtain,

{x}^{2}  - 2x \:  \:  \:  \:  +  {y}^{2}  + 8y \:  \:  \:  \:  = 47


We now add half the square of the coefficient of
x \: and \: y
to both sides of the equation to get,


{x}^{2}  - 2x  + ( - 1) ^{2}  +  {y}^{2}  + 8y  +  {(4)}^{2} = 47 + ( - 1) ^{2}  +   {4}^{2}



We now got two perfect squares on the left hand side of the equation,


(x - 1)^{2}   +  {(y + 4)}^{2} = 47 + 1 +   16


(x - 1)^{2}   +  {(y + 4)}^{2} =64



(x - 1)^{2}   +  {(y + 4)}^{2}  =  {8}^{2}



By comparing to the general formula of the circle,


{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}


We can see that the radius is 8.
4 0
3 years ago
Read 2 more answers
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