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2 years ago

I need help with this problem y=5x-3

Mathematics

1 answer:

defon2 years ago

3 0

Answer:

Slope= 5

y intercept= (0,-3)

Step-by-step explanation:

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Area addition and subtraction

telo118 [61]

Answer:Area of the shaded region is 73.6 cm^2

Step-by-step explanation:

The circle is divided into two sectors. The Smaller sector contains the triangle. The angle that the smaller sector subtends at the center of the circle is 80 degrees. Since the total angle at the center of the circle is 360 degrees, it means that the angle that the larger sector subtends at the center would be 360 - 80 = 280 degrees

Area of a sector is expressed as

Area of sector = #/360 × πr^2

# = 280

r = 5 cm

Area of sector = 280/360 × 3.14 × 5^2

Area of sector = 61.06 cm^2

Area of the triangle is expressed as

1/2bh = 1/2 × 5 × 5 = 12.5

Area of the shaded region = 61.06 +

12.5 = 73.6

7 0

3 years ago

25 is 45% of what number

Oksi-84 [34.3K]

Answer: 55.56

Step-by-step explanation:

Let the unknown number be k

(45 x k) / 100 = 25

45k/100 = 25

multiply both sides by 100

45k = 25 x 100

45k = 2500

divide both sides by 45

k = 2500/45

k = 55.56

6 0

3 years ago

What are some examples if irratinal numbers

Ivan

Pi aka 3.14 is a very commonly know irrational number

4 0

3 years ago

Read 2 more answers

The sum of 3 consecutive integers is 60. What is the value of the third integer?

Scorpion4ik [409]

Answer:

x=19

Step-by-step explanation:

The consecutive integers will be x, x+1 and x+2 since consecutive integers have a pattern.

So, the equation is x+x+1+x+2=60

Solve:

x+x+1+x+2=60

3x+3=60

Subtract 3 on both sides:

3x+3-3=60-3

3x=57

Divide by 3

3x/3=57/3

x=19

3 0

3 years ago

April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how

Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

$a \times 8 + c \times 5 = 495$

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

Substitute c = 35 in eqn 3

a = 75 - 35

Thus 40 adult tickets were sold and 35 children tickets were sold

8 0

3 years ago