Answer:
These properties are basically the inverse of each other.
Explanation:
- Electronegativity is the tendency of an atom to attract an electron and make it a part of its orbital.
Ionization enthalpy, is the energy required to remove an electron from an atom.
- More electronegative atoms have high ionization enthalpies If the energy required to remove an electron is less, i.e. the atom has more tendency to give electron, it would thus have less tendency to take electron.
- Values and tendency of electronegativity in the periodic table: In general, the electronegativity of a non‐metal is larger than that of metal. For the elements of one period the electronegativities increase from left to right across the periodic table. For the elements of one main group the electronegativities decrease from top to bottom across the periodic table. To the subgroup elements, there’s no regular rule.
- Values and tendency of ionization potential in the periodic table: The first ionization energy is the energy which is required when a gaseous atom/ion loses an electron to form a gaseous +1 valence ion. The energy which is required for a gaseous +1 valence ion to loose an electron to form a gaseous +2 valence ion, is called the second ionization energy of an element. In general, the second ionization energy is higher than the first ionization energy of an element.
The first ionization energies of the elements of one period increase from the left to the right across the periodic table. According to the elements of main group, the first ionization energies generally decreases from top to bottom across the periodic table.
Answer:
B: It is extremely reactive
Explanation:
Potassium metal is also soft and white with a silvery lustre, has a low melting point, and is a good conductor of heat and electricity.
Answer:
Mass and Velocity
Explanation:
hope this is the right answer might wrong tho
Answer:
20.2 °C
Explanation:
When the pressure and number of moles are constant, Charles's law may be used to solve for temperature:
T₁/V₁ = T₂/V₂ >> T₂ = T₁ (V₂/V₁)
Expressions for the volumes can be substituted and simplified:
T₂ = T₁ (V₂/V₁) = T₁ (4/3πr₂³/4/3πr₁³) = T₁ (r₂³/r₁³)
Substituting in values in the equation (where the radius r is half of the diameter) gives:
T₂ = T₁ (r₂³/r₁³) = (19.0°C) x ((51.0cm/2)³/(50.0cm/2)³) = 20.2 °C