Answer:
8.63%
Explanation:
The expected rate of return on the bond can be determined using a financial calculator bearing in mind that the calculator would be set to its end date before making the following inputs:
N=17(number of annual coupons in 17 years)
PMT=100(annual coupon=face value*coupon rate=$1000*10%=$100)
PV=-1120(the current price is $1,120)
FV=1000(the face value of the bon is $1000)
CPT
I/Y=8.63%
EXCEL APPROACH:
=rate(nper,pmt,-pv,fv)
nper=N=17
=rate(17,100,-1120,1000)
rate=8.63%
Ready Repair Service enters into a contract to fix washers and dryers in Scrub n' Dry Company's coin-operated laundries. If Ready Repair breaches by only partially performing the contract, Scrub n' Dry can C. sue Ready Repair for compensatory and consequential damages.
Scrub n' Dry can sue Ready Repair if they do not hold up the full contract that was agreed on. Consequential damages are a type of compensatory damage. Since Scrub n' Dry did not receive all of the compensation they were entitled to based on their initial agreement they can sue to be awarded the funds that were lost. Compensatory damages are only meant to compensate a person for what they lost not punish the other company/individual.
<span>$65,472.34
The formula for compound interest is:
A = P(1+r/n)^(nt)
where
A = Future amount
P = Principle
r = annual interest rate
n = number of periods per year
t = number of years
So let's substitute the known values and calculate:
A = P(1+r/n)^(nt)
A = 46000(1+0.04/1)^(1*9)
A = 46000(1+0.04)^9
A = 46000(1.04)^9
A = 46000(1.423311812)
A = 65472.34
So $65,472.34 needs to be paid back after 9 years.</span>
already answered this question for you in a previous post. Please do not post the same question 6 times in the thread.
Answer:
the cost for the running the boarding school for 600 students is $61000
Explanation:
Let x be the constant cost and y be the variable cost . then according to the given condition
total cost=<em><u> x +25y= $3500-------1</u></em>
<u><em>x +50y= $6000----------2</em></u>
Subtracting 1 from 25y= 2500
<u><em>y= 2500/25= $100-----------3</em></u>
<em><u>Putting the value of y from 3 in 1 </u></em>
x+ 25(100)= 3500
x+ 2500= 3500
<u><em>x= 1000$---------4</em></u>
<u><em>Putting the value of y from 3 in 2</em></u>
x+ 50(100)= 6000
x+ 5000=6000
<u><em>x= 1000$----------5</em></u>
<u><em>Putting the values of x and y in 1 for 600 students</em></u>
1000+ 600(100) =1000+ 60000= $61000