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Sliva [168]
3 years ago
7

The cost of the ski team's trip is represented by the question: Where

Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0
The answer is: 30 skiers were participating in the ski trip.

Method:

$50S = $1,850 - $350 = $1,500

S = 1,500/50 = 30

Therefore, 30 skiers went on the trip

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Use the figure to find the measures. Apothem=
ad-work [718]
See the attached picture with letters to better understand the problem

we know that
the figure is a regular hexagon

A regular hexagon has:

<span>Interior Angles of <span>120°
</span></span>so
in the triangle ABC
BC=2 units
∠ABC=30°
∠BAC=60°

tan 30°=AC/BC
solve for AC
AC=BC*tan 30°-------> AC=2*(√3)/3
<span>Apothem is equal to AC
</span>Apothem=(2/3)√3

the answer is
(2/3)√3

3 0
3 years ago
Evaluate 0.1m+8-12n0.1m+8−12n0, point, 1, m, plus, 8, minus, 12, n when m=30m=30m, equals, 30 and n=\dfrac14n= 4 1 ​ n, equals,
Rom4ik [11]

Answer:

8

Step-by-step explanation:

We are required to evaluate:

0.1m+8-12n

When m=30, n=\frac{1}{4}

Substituting these values into the expression, we have:

0.1m+8-12n=0.1(30)+8-12(\frac{1}{4})\\=3+8-\frac{12}{4}\\=3+8-3\\=8

8 0
3 years ago
Read 2 more answers
At a fruit stand, 4 limes cost 80 cents. Which equation can be used to find the cost, y, in cents for x number of lines
Andreyy89
Y=20x is the answer
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3 years ago
How many different strings of length 12 containing exactly five a's can be chosen over the following alphabets? (a) The alphabet
N76 [4]

Answer:

Part (A) The required ways are 792.

Part (B) The required ways are 101376.

Step-by-step explanation:

Consider the provided information.

Part (A) The alphabet {a, b}

The length of strings is 12 that containing exactly five a's.

The number of ways are: \frac{12!}{5!7!}

After filling "a" we have now 7 places.

For 7 places we have "a" and "b" alphabet but we already select a's so now the remaining place have to fill by "b" only.

Thus, the required ways are: \frac{12!}{5!7!}\times 1=792

Part (B) The alphabet {a, b, c}

We have selected five a's now we have now 7 places.

For 7 places we have "b" and "c".

Thus, there are 2 choices for each 7 place that is 2^7

Therefore the total number of ways are: 792\times 2^7=101376

Thus, the required ways are 101376.

7 0
4 years ago
What is the general form of the equation for the given circle?
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Hhhhhhhhahahahahahahahahahahaahabahahah 4.7
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