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kifflom [539]
3 years ago
7

6×10(6)+7×10(5)+3×10(2)+8×10+2

Mathematics
1 answer:
anastassius [24]3 years ago
7 0

Answer:

852

6×10(6)+7×10(5)+3×10(2)+8×10+2= 852

Step-by-step explanation:

ORDER OF OPERATIONS Will really help you solve this long problem.

Order of operations is PEMDAS.

P-parenthesis

E-exponents

M-multiplication

D-division

A-addition

S-subtraction

6)(10)(6)+(7)(10)(5)+(3)(10)(2)+(8)(10)+2

=(60)(6)+(7)(10)(5)+(3)(10)(2)+(8)(10)+2

=360+(7)(10)(5)+(3)(10)(2)+(8)(10)+2

=360+(70)(5)+(3)(10)(2)+(8)(10)+2

=360+350+(3)(10)(2)+(8)(10)+2

=710+(3)(10)(2)+(8)(10)+2

=710+(30)(2)+(8)(10)+2

=710+60+(8)(10)+2

=770+(8)(10)+2

=770+80+2

=850+2

=852

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* AD is congruent to DC and BD <em>true</em>

* m∠B = 90° <em>true</em>

<u>* The measure of arc AC is equal to the measure of arc AB </u><u><em>not be true</em></u><em> ( The right answer  )</em>

* The measure of arc AB is equal to measure of arc BC <em>true</em>

Step-by-step explanation:

∵ D is the center of the circle and A , B and C are points on the circle

∴ AD , DB and DC are radii on the circle D

∴ AD ≡ DC ≡ DB

∵ AC passing through point D which is the center of the circle

∴ AC is the diameter of the circle D

∵ ∠B is opposite to the diameter of the circle and vertex B lies on the circle

∵ ∠B is an inscribed angle and  ∠ADC  is a central angle subtended by the same arc AC

∴m∠B = half m∠ADC

∵ m∠ADC = 180°

∴ m∠B = 90°

∵ The measure of arc AC = 180°

∵ ΔABC is isosceles and m∠B = 90°

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∵ ∠ACB is an inscribed angle subtended by arc AB

∴ m∠ACB = half measure of arc AB

∵ The measure of arc AB = 45° × 2 = 90°

∴ The measure of arc AC ≠ the measure of arc AB

∵ Δ ABC is an isosceles triangle and m∠B = 90°

∴ AB = BC

∵ AB subtended by arc AB

∵ BC subtended by arc BC

∴ The length of arc AB = the length of arc BC

∵ If two arcs are equal in length, then they will be equal in measure

∴ The measure of arc AB is equal to the measure of arc BC

3 0
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